Answer:
0
Step-by-step explanation:
Plug 2 points into the equation y2-y1/x2-x1. In this case, I picked (0,-1) and (1,-1). This will make the equation -1--1/1-0. Simplify this to get 0/1 which is equal to 0. Therefore, the slope is 0.
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Answer:
The domain of the function is all real values of x, except
and 
Step-by-step explanation:
We are given the following function:

It's a fraction, so the domain is all the real values except those in which the denominator is 0.
Denominator:
Quadratic equation with 
Using bhaskara, the denominator is 0 for these following values of x:



The domain of the function is all real values of x, except
and 
The question illustrates a linear equation, and the equation that represents the greatest horizontal height is H = 2V + 3
<h3>How to determine the equation?</h3>
From the complete question, we have the following highlights:
The greatest horizontal height is three more than twice the greatest vertical length.
This means that:
H = 2 * V + 3
Evaluate the product
H = 2V + 3
Hence, the equation that represents the greatest horizontal height is H = 2V + 3
Read more about linear equation at:
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Answer:
1130.97 (last option)
Step-by-step explanation:
Basically its the circumference times 12. Circumference of the circle is 2 * 15 * pi which is 30 pi. 30pi * 12 is 360pi which is around 1130.97 or the last option
Graphs of linear functions
Since we are graphing a line, if we have two points we can plot the whole line
We evaluate the line in two points in order to locate two places where it passes through. We say y = h(x)
1. If x = 0 then
h(x) = - 5(0) +3
= 0 + 3
= 3
Then y = 3
2. If x = 2 then
h(x) = - 5(2) +3
= -10 + 3
= -7
Then y = -7
Now, we have two points: (0, 3) and (2, -7)
We locate them and then we plot the only straight line that passes through both points