Answer:
First find the rate for a year .
5000 dollars × 6.25 = 31 250
After you find it multiply it by 20 ( because there are 20 years)
31 250 × 20 = 625000
Answer:
The probability that at least 1 car arrives during the call is 0.9306
Step-by-step explanation:
Cars arriving according to Poisson process - 80 Cars per hour
If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67 X ≅ Poisson (λ = 2.67)
Now, we find the probability: P(X≥1)
P(X≥1) = 1 - p(x < 1)
P(X≥1) = 1 - p(x=0)
P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!
P(X≥1) = 1 - e^-2.67
P(X≥1) = 1 - 0.06945
P(X≥1) = 0.93055
P(X≥1) = 0.9306
Thus, the probability that at least 1 car arrives during the call is 0.9306.
Gordon read a total of 35 pages, so if there is p pages read per day and 10 days you'd have something that looks like this: 35 = 10p.
Answer:
9
Step-by-step explanation:
x didn't change in value, y changed by 9
the distance between the two points is 9
The less coefficient in front of x^2, the wider graph
the smallest coefficient is 1/5 , so the widest graph is y=(1/5)x²
