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Illusion [34]
3 years ago
7

Find the indicated real nth root(s) of a. n=2, a=100

Mathematics
1 answer:
rosijanka [135]3 years ago
7 0
A=50 is the nth term for  a to equal 100
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A = ?<br> b = ?<br> Please explain as well :)
sweet [91]

Answer:

a = 25 , b = 14

Step-by-step explanation:

For A

a/5 + 3 = 8

a/5 = 8 - 3

a/5 = 5

Cross multiply

a = 5 * 5

a = 25

For B

3b/7 - 1 = 5

3b/7 = 5 + 1

3b/7 = 6

Cross multiply

3b = 42

b = 42 / 3

b = 14

Hope it will help

5 0
3 years ago
Cuál es primer número natural o entero positivo que conoces​
____ [38]

Answer:

Los números naturales incluyen solo enteros positivos y comienzan desde 1 hasta infinito

5 0
2 years ago
Change the fraction to a percent.
ziro4ka [17]
The fraction in the picture is  1/8 . 
That's equivalent to 12.5 %.
____________________________________

Maybe what you want is the whole mixed number changed to percent.

-- The  5  alone is  500% .

-- The  1/8  alone is  12.5% .

-- When you puttum together and addum up,

                 (5 + 1/8)  =  (500%  +  12.5%)  =  512.5%  .
8 0
3 years ago
Read 2 more answers
Calculate the area of the circle. round your answer to the nearest hundredth
Artemon [7]
52 is the answer I believe
8 0
3 years ago
What is the following product? (2 square root 7+3 square root 6)(5 square root 2+4 square root 3)
Xelga [282]

(2\sqrt7+3\sqrt6)(5\sqrt2+4\sqrt3)\qquad\text{use distributive property}\\\\=(2\sqrt7)(5\sqrt2)+(2\sqrt7)(4\sqrt3)+(3\sqrt6)(5\sqrt2)+(3\sqrt6)(4\sqrt3)\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{12}+12\sqrt{18}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{4\cdot3}+12\sqrt{9\cdot2}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt4\cdot\sqrt3+12\sqrt9\cdot\sqrt2\\\\=10\sqrt{14}+8\sqrt{21}+(15)(2)\sqrt3+(12)(3)\sqrt2\\\\=\boxed{10\sqrt{14}+8\sqrt{21}+30\sqrt3+36\sqrt2}

5 0
3 years ago
Read 2 more answers
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