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horrorfan [7]
3 years ago
5

Ginger wants to fill her new swimming pool. She has two pumps; the larger pump takes 40 minutes to fill the pool, and the smalle

r one takes 60 minutes. How long will it take to fill the pool if both pumps are working?
Mathematics
2 answers:
Talja [164]3 years ago
5 0

As per the problem,

The larger pump takes 40 minutes to fill the pool.

The smaller one takes 60 minutes.

When both the pumps are working , let the time taken be x minutes , then we can write

\frac{1}{x}=\frac{1}{40}+\frac{1}{60}\\ \\ \text{Make the denominator equal we get}\\ \\    \frac{1}{x}=\frac{1}{40}*\frac{60}{60}+\frac{1}{60}*\frac{40}{40}\\ \\   \frac{1}{x}=\frac{60}{2400}+\frac{40}{24000}\\ \\   \text{Simplify we get}\\ \\ \frac{1}{x}=\frac{60+40}{2400}\\ \\ \frac{1}{x}=\frac{100}{2400}\\ \\ \frac{1}{x}=\frac{1}{24}\\ \\ x=24\\

Hence, when both the pumps works together, Time taken =24 minutes.

Neko [114]3 years ago
3 0
It will take one hundred minutes
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A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
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Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

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Bas length of box=b

Height of box=h

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We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=2b^2+4bh

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2bh=18-b^2

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Differentiate w. r.t b

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b=\pm \sqrt{6}

b=\sqrt{6}

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

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\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

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h=\frac{18-6}{2\sqrt{6}}

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h=\sqrt{6}

b=h=\sqrt{6} m

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