Answer:
#1: inequality form: x ≤ –1 or x ≥ 2
interval notion: ( -∞,-1] U [2,∞)
#2: false/no solution
#3: A) point form: (3,9)(-1,1)
equation form: x= 3,y=9 and x= -1,y=1
B)point form: (1,7)(7,1)
equation form: x=1,y=7 and x=7,y=1
Step-by-step explanation:
#1: solve for x by simplifying both sides of the inequality, then isolating the variable.
#2: N/A
#3: solve for the first variable in one of the equations, then substitute the results into the other question.
First, you multiply 6 by 6, since one-sixth of all her dog toys are red.
6×6=36.
Next, we put them in fraction form just to check.

Next, we simplify it to see if we get one-sixth.
After it's simplified we get

That means she has
36 dog toys.
Have a nice day! :)
I'll give you an example:
Find the first and third quartiles using this set of data - 3, 5, 7, 8, 9, 11, 15, 16, 20, 21.
Step 1: Put the numbers in order.
3, 5, 7, 8, 9, 11, 15, 16, 20, 21.
Step 2: Make a mark in the center of the data:
3, 5, 7, 8, 9, | 11, 15, 16, 20, 21.
Step 3: Place parentheses around the numbers above and below the mark you made in Step 2–it makes Q1 and Q3 easier to spot.
(3, 5, 7, 8, 9), | (11, 15, 16, 20, 21).
Step 4: Find Q1 and Q3
Q1 is the median (the middle) of the lower half of the data, and Q3 is the median (the middle) of the upper half of the data.
(3, 5, 7, 8, 9), | (11, 15, 16, 20, 21). Q1 = 7 and Q3 = 16.