Answer:
The statement is false.
Step-by-step explanation:
To begin an indirect proof, you assume the converse of what you intend to prove is true. This is false.
Rather the correct answer is that to begin an indirect proof, you assume the inverse of what you intend to prove is true.
The converse can be either true or false, depending on what the original statement is, so assuming the converse is pointless.
Answer:
48
Step-by-step explanation:
To get the area of anything you multiply the width by the length.
6×8=48
Start by writing it out like this:
17.50
<u>* 2.48 </u>
Make sure that all the places are in correct order. Notice that I added a ZERO in the place that had nothing there.
Move the decimal point so everything is a whole number. You have moved it 4 times.
Now, starting from 8, multiply it by 0, then 5, then 7, and lastly, 1. Now go to the next number (4) and do the same, this time though, put a zero in the first spot. Every new number, add another zero.
After you are done, add them up. Now move the decimal point starting from the right and into the number 4 times. Take out the zeros.
Your answer should be: 43.4
Answer: $85.38
Step-by-step explanation:
67.95 - 60% + 7% = $67.42
18.49 - 60% + 7% = 17.96
67.42 + 17.96 = $85.38
Answer:
A) 22812 hotdogs per run
B) 75 runs/yr
C) 4 days in a run
Step-by-step explanation:
We are given;
Production rate;p = 5750 per day
Steady Usage rate;u = 270 per day
Setup cost of hotdog;S = $67
Annual carrying cost (H) = 47 cents = $0.47 per hot dog
No. of Production days; d = 297 days
A) Let's first find the annual demand given by the formula;
Annual demand;D = pd
D = 5750 × 297
D = 1707750 hot dogs/yr
Now, formula for optimal run size is given by;
Q_o = √[(2DS/H) × (p/(p - u))]
Plugging in the relevant values gives;
Q_o = √[(2 × 1707750 × 67/0.47) × (5750/(5650 - 270))]
Q_o =√520375454.7971209
Q_o = 22812 hotdogs per run
B) formula for Number of runs per year is given as;
No. of Runs = D/Q₀
Thus;
no. of runs = 1707750/22812
no. of runs ≈ 75 runs/yr
C) Length of a run is given by the formula;
Length = Q₀/p
Length = 22812/5750
Length ≈ 4 days in a run
