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Rina8888 [55]
3 years ago
14

Which of the following is not the same as postive 7​

Mathematics
1 answer:
shusha [124]3 years ago
8 0
Am I suppose to be looking at a picture?
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Factor the polynomial x2 + 2x – 3x – 6 by double grouping. Group terms with common factors: (x2 + 2x) + (– 3x – 6) Factor the GC
garik1379 [7]

We have been given a polynomial and we are asked to factor our polynomial by double grouping.

x^{2} +2x-3x-6

First of all we will group terms with common factors. We can see that x^{2} and 2x have a common factor x. Common factor of -3x and -6 is -3.

x^{2} +2x-3x-6

(x^{2} +2x)+(-3x-6)

Now we will factor out Greatest Common Factor from each group.

x(x+2)-3(x+2)

After factoring out GCF from each group we got (x+2) as our common binomial.  Now we will write our polynomial as a product of two binomials as:

(x+2)(x-3)

Therefore, our polynomial as a product of two binomials will be (x+2)(x-3).  

8 0
3 years ago
Read 2 more answers
Simplify log(16x²) ± 2㏒(1÷×)
sp2606 [1]

Answer: just simplify condense it then your answer will be log(16)

8 0
3 years ago
Juana is measuring two pyramids whose base are isosceles right triangles. The second pyramid has the same height, but has 9 time
Zigmanuir [339]

9514 1404 393

Answer:

  3 times the smaller triangle base

Step-by-step explanation:

The volume is proportional to the height and to the area of the base.

If the height is unchanged, the larger pyramid must have a triangular base with an area that is 9 times the smaller base area.

Since the bases are similar, the area ratio is the square of the side length ratio. The side lengths of the larger base triangle must be √9 = 3 times the side lengths of the smaller base triangle.

7 0
3 years ago
Janice spent $54 to buy some pairs of pants. Each pair of pants cost the same whole dollar amount. How many pairs of pants could
RideAnS [48]
I think you should add one dollar each time for a pair a pants she bought
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3 years ago
Solve the following system of equations:
grin007 [14]
<span>A) 4x − 2y − z = −5
B) x − 3y + 2z = 3
C) 3x + y − 2z = −5
Looking at ALL 4 solutions, x =0 in all of them.
So, let's say x = 0, eliminate the "x's" and just keep equations B and C
</span>
<span>B) -3y + 2z = 3
C) y − 2z = −5
</span>Add B) and C)
-2 y = -2
y = 1

<span>1 − 2z = −5
</span>-2z = -6

z = 3

and x = 0


7 0
3 years ago
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