Answer:
R2->R3
Step-by-step explanation:
Answer:
<em>Value</em><em> </em><em>of</em><em> </em><em>p</em><em> </em><em>is</em><em> </em><em>14</em>
Step-by-step explanation:
![given \: complementary \: angles \: add \: up \: to \: 90 \: degrees \\ then \\ 2p + 6 + 4p = 90 \\ 6p + 6 = 90 \\ 6(p + 1) = 90 \\ p + 1 = \frac{90}{6} \\ p + 1 = 15 \\ p = 15 - 1 \\ p = 14](https://tex.z-dn.net/?f=given%20%5C%3A%20complementary%20%5C%3A%20angles%20%5C%3A%20add%20%5C%3A%20up%20%5C%3A%20to%20%5C%3A%2090%20%5C%3A%20degrees%20%5C%5C%20then%20%5C%5C%202p%20%2B%206%20%2B%204p%20%3D%2090%20%5C%5C%206p%20%2B%206%20%3D%2090%20%5C%5C%206%28p%20%2B%201%29%20%3D%2090%20%5C%5C%20p%20%2B%201%20%3D%20%20%5Cfrac%7B90%7D%7B6%7D%20%20%5C%5C%20p%20%2B%201%20%3D%2015%20%5C%5C%20p%20%3D%2015%20-%201%20%5C%5C%20p%20%3D%2014)
<em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>
Answer:
cosR = ![\frac{5}{13}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B13%7D)
Step-by-step explanation:
assuming the right triangle has ∠ Q = 90° with legs 5 and 12
then this is a 5- 12- 13 right triangle with hypotenuse PR = 13 cm
then
cosR =
=
= ![\frac{5}{13}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B13%7D)
C. Alternate interior angles are formed by a transverse line intersecting two parallel lines . They are located between the two parallel lines but on opposite sides of the transverse line