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2 years ago

Please help! ASAP

Mathematics

1 answer:

vaieri [72.5K]2 years ago

5 0

891 were sold
.55x1800= 990
10% of 990 roses is 99 (99 is left over)
990-99= 891

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Pizzas cost $12 each, tax included. You decide to give the delivery driver a $6 tip.

Y_Kistochka [10]

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Step-by-step explanation:

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2 years ago

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Find the area of the shape shown below.

Scilla [17]

Answer:

Step-by-step explanation:

Area of a trapezoid can be found using the following formula:

A= base 1 + base 2 / 2 times the height

plug it in

A= 6 + 2/2 times 2

A= 8

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3 years ago

If the zeros are 8 and 1/2, what are the factors?

timurjin [86]

Answer:

Step-by-step explanation:

Factors : (x - 8) (x- 1/2) or

(x - 8 ) (2x - 1)

Equation: (x - 8)(2x - 1) = x*2x + x*(-1) -8*2x -8*(-1)

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3 years ago

Which one would be correct

nirvana33 [79]

Answer:

Step-by-step explanation:

The graph starts from 55 and stops at 65 and the only answer that is between that range is D.

Hope it helps:-)

3 0

3 years ago

Which is the simplified form of the expression

Elina [12.6K]

Answer:

$\displaystyle A=\frac{ 4 }{ x^{14} y^{8}}$

Step-by-step explanation:

<u>Properties of Powers</u>

The algebraic expression called power has the form x^y where x is called the base and y is called the exponent.

Powers have some properties, some of which we'll recall below

$(x^a)^b=x^{ab}$

$(x^a)(x^b)=x^{a+b}$

$\displaystyle \frac{x^a}{x^b}=x^{a-b}$

$\displaystyle x^{-a}=\frac{1}{x^a}$

$\displaystyle x^{a}=\frac{1}{x^{-a}}$

We'll use those properties to simplify the expression

$\displaystyle A=\left( \frac{ (2)^{-3}(x^{-3}) (y^2) }{(4^{-2}) (x^4) (y^6)} \right)^2$

Taking the power 2 of every term

$\displaystyle A=\frac{ (2)^{-6}(x^{-6}) (y^4) }{(4^{-4}) (x^8) (y^{12})}$

Moving the terms with negative exponent to its opposite side

$\displaystyle A=\frac{ (2)^{-6} (4^{4})(y^4) }{ (x^8)(x^{6}) (y^{12})}$

Operating the explicit same bases

$\displaystyle A=\frac{ (2)^{-6} (4^{4}) }{ (x^{14}) (y^{12-4})}$

Since $4^4=(2^2)^4=2^8$

$\displaystyle A=\frac{ (2)^{-6} (2^8) }{ (x^{14}) (y^{12-4})}$

Operating the remaining like bases subtractions

$\displaystyle A=\frac{ (2^2) }{ (x^{14}) (y^{8})}$

Finally

$\displaystyle A=\frac{ 4 }{ x^{14} y^{8}}$

5 0

3 years ago