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Darya [45]
3 years ago
6

Find the slope given the points (1,4) and (5,9)

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

the slope is 5/4

Step-by-step explanation:

use the formula y2 - y1 over x2 - x1, and plug in the coordinates into that

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The volume of two similar solids are 128 m3
arsen [322]

Answer:

Solution given:

The volume of two similar solids are 128 m³

and 250 m³.

surface area of larger solid is 250m²

<u>let</u><u> </u><u>surface</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>smaller</u><u> </u><u>solid</u><u> </u><u>be</u><u> </u><u>x</u><u>.</u>

<u>Since</u><u> </u><u>they</u><u> </u><u>are</u><u> </u><u>similar</u>

\frac{250}{128}   =  \frac{250}{x}

x=128

the surface are of the

smaller solid is 128m²

8 0
3 years ago
Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x
OleMash [197]

ANSWER



x=1.39 to the nearest hundredth.



EXPLANATION



We have the equation,



0=2x^2+3x-8



Which can be rewritten as



2x^2+3x-8=0

The question demands the use of the quadratic formula.

Comparing this to the general quadratic equation;

ax^2+bx+c=0


a=2,b=3,c=-8


The quadratic formula is given by;


x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}


We now substitute all the values in to the formula;


x=\frac{-3\pm\sqrt{(3)^2-4(2)(-8)}}{2(2)}

We simplify to obtain;

x=\frac{-3\pm\sqrt{9+64}}{4}


x=\frac{-3\pm\sqrt{73}}{4}


We now split the plus or minus sign to obtain;


x=\frac{-3-\sqrt{73}}{4}


This implies that;


x=-2.89

Or

x=\frac{-3+\sqrt{73}}{4}


This will evaluate to;


x=1.39

Hence, the positive solution rounded to the nearest hundredth is

x \approx 1.39

6 0
3 years ago
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Minchanka [31]
170 - (58.35 + 85.80) = 25.85
6 0
3 years ago
what is the value of the X variable in the solution to the following system of equations for 4x+ 2y =6 x-y=3
blagie [28]
X=1,y=1

1 )4x+2y=6
2 ) x -y=3

2(x2) ) 2x - 2y=6
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3 years ago
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0.932 g = ----------- mg​
Brut [27]

Answer:

932

Step-by-step explanation:

3 0
3 years ago
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