Answer:
Solution given:
The volume of two similar solids are 128 m³
and 250 m³.
surface area of larger solid is 250m²
<u>let</u><u> </u><u>surface</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>smaller</u><u> </u><u>solid</u><u> </u><u>be</u><u> </u><u>x</u><u>.</u>
<u>Since</u><u> </u><u>they</u><u> </u><u>are</u><u> </u><u>similar</u>

x=128
the surface are of the
smaller solid is 128m²
ANSWER
to the nearest hundredth.
EXPLANATION
We have the equation,

Which can be rewritten as

The question demands the use of the quadratic formula.
Comparing this to the general quadratic equation;


The quadratic formula is given by;

We now substitute all the values in to the formula;

We simplify to obtain;


We now split the plus or minus sign to obtain;

This implies that;

Or

This will evaluate to;

Hence, the positive solution rounded to the nearest hundredth is

X=1,y=1
1 )4x+2y=6
2 ) x -y=3
2(x2) ) 2x - 2y=6
Answer:
932
Step-by-step explanation: