Answer:
Positive, because the products (–5)(–3) and (–8)(–6) are positive, and the product of two positive numbers is positive
Step-by-step explanation:
There are an even number of negative factors, so the product is positive:
Positive, because the products (–5)(–3) and (–8)(–6) are positive, and the product of two positive numbers is positive
I hope this helps you
x.3x+x.(-1)+5.3x+5.(-1)-(x^2-2.4.x+16)
3x^2-x+15x-5-x^2+8x-16
2x^2+22x-21
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
Answer:
Option C)
Step-by-step explanation:
Here we are given with the expression 
The GCF of 
and 12 is 3
Hence we take 3 as GCF and bring it in front of the bracket.
It can not be factorise furthure as there is no GCF of 25 and also there is no rule for sum of squares so that we may apply it on this. Hence the answer would be
Option C)
