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3 years ago

How do u friend someone on brainlest and whaat is 1 +1 help never leaned how to count bc im number 1

Mathematics

2 answers:

Dvinal [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Ne4ueva [31]3 years ago

5 0

Answer:

You go to their profile and under their name right next to where it say's "Thanks" There is a icon of a person with a plus sign. Click that and it will send that person a friend request.

1+1=2 :))

Step-by-step explanation:

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What is the value of x?<br><br> Enter your answer in the box.<br><br> x =

Dmitry_Shevchenko [17]

Answer: x = 20

We know opposite angles are equivalent so we can set both of these expressions equal to each other to solve for x.

3x + 50 = 6x - 10
50 = 3x - 10 (subtract 3x from both sides)
60 = 3x (add 10 to both sides)
20 = x (divide both sides by 3)

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3 years ago

Calculate the standard deviation of the data set below. (7, 9, 10, 11, 13)

Reil [10]

I think it's 2.2. I apologize if it's incorrect

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3 years ago

Read 2 more answers

What is the area of this tile 4in 1in

nikitadnepr [17]

Answer:

4 in

Step-by-step explanation:

area is inside you have to multiply

4 times 1 is 4

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3 years ago

In a flower garden, there are 4 tulips for every 9 daisies. If there are 24 tulips, how many daisies are there? Please help i wi

miss Akunina [59]

54 daisies is the answer

Hope you have a good day!

4 0

3 years ago

The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

$AV = \frac{y(t2) - y(t1)}{t2 - t1}$

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

$AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6$

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii) t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

$AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8$

So the average speed is -128.9 ft/s

iii) t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

$AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16$

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0

3 years ago