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3 years ago

What is the inverse function of f(x) = x/x-2

Mathematics

2 answers:

elena55 [62]3 years ago

5 0

The Answer is A because it's Marie and I have been working with the other kids Jimmie I know I did it

lina2011 [118]3 years ago

3 0

F-1(x)=2x/x-1
Is the correct answer

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Find the area of the figure below

Serhud [2]

Easy

the easiest way is to imagine that you have a rectangle with a corner cut off
the area of the figure=area of rectangle-area cut off

area that was cut off was a triangle

area of rectangle=length times width
area of triangle=1/2base times height

so we draw imaginary lines like in attachment
find area of rectangle
legnth=9 inch
width=9 inch
area=9 times 9=81 in^2

triangle
the top part is ?+5=9, so the base of triangle=4
the side is ?+4=9, so the base is 5
area=1/2 times 4 times 5=10 in^2

area=rectangle-triangle
area=81-10=71 in^2

7 0

3 years ago

Read 2 more answers

Can someone help me please I would appreciate it.

Dmitry_Shevchenko [17]

The answer is c to my calculations.

4 0

3 years ago

Find the range of ƒ(x) = 3g – 5 for the domain {–1.5, 2, 4}

timofeeve [1]

-1.5 ------ f(x) = 3(-1.5) - 5
= -4.5 -5
= 9.5

2 -------- f(x) = 3(2) - 5
= 6 -5
= 1

4 -------- f(x) = 3(4) - 5
= 12 - 5
= 7
(9.5, 1 , 7)

6 0

3 years ago

A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021

egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

$\displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}$

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

$\displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}$

Therefore, for the last term we have;

$\displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}$

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

$\displaystyle \frac{A}{2} = \mathbf{ 1011 \cdot \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460} \right)}$

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2} +\frac{1}{2} - \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022} \right)$

Which gives;

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2022} \right)$

$\displaystyle A = 2 \times 1011 \cdot \left(1 - \frac{1}{2022} \right) = \frac{1032231}{511} \approx \mathbf{2020.022}$

A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0

2 years ago

Read 2 more answers

Carla is age 32. how many quarters of coverage does she need to be fully insured

never [62]

According to my research, And I would take this with a grain of salt since I am not a insurance rep . You can earn up to four quarters of coverage each year. In order to be fully insured for Social Security Disability purposes, you must have earned at least one quarter of coverage per year for each year since you turned 21 years old. A minimum of six quarters of coverage is needed to be fully insured at any age so maybe Six quarters, at least according to SSD .
Hope I helped or shed some light !.

7 0

3 years ago