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pav-90 [236]
2 years ago
6

Find the slope of the line that contains the points (-8, -2) and (-17, 4).

Mathematics
2 answers:
amid [387]2 years ago
6 0

Answer:

<h2>-2/3 </h2>

Step-by-step explanation:

<h3>m=y2-y1/x2-x1
m=4-(-2)/-17-(-8)
m=4+2/-17+8
m=6/-9
m=-2/3 </h3>
IRINA_888 [86]2 years ago
6 0
<h2><u>S</u>O<u>L</u>V<u>I</u>N<u>G</u></h2>

\Large\maltese\underline{\textsf{A. \space What is Asked}}

Find the slope of the line that contains the points (-8,-2) and (-17,4)

\Large\maltese\underline{\textsf{B.\space This problem has been solved!}}

If we are given two points, we can easily find the slope of the line that passes through the points. With points (y₂, y₁) and (x₂, x₁), the slope is \bf{\dfrac{y2-y1}{x2-x1}.

Similarly, with points (-8,-2) and (-17,4) the slope is.

\bf{\dfrac{4-(-2)}{-17-(-8)}} | as we can see, it is possible to simplify this further

\bf{\dfrac{4+2}{-17+8}} | simplify

\bf{\dfrac{6}{-9} | reduce

\bf{-\dfrac{2}{3}}

\rule{300}{1.7}

\bf{Result:}

                    \bf{=-\dfrac{2}{3}}

\boxed{\bf{aesthetic\not101}}

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