Question

One number is six less than a second number. Twice the first is 4 more than times 6 the second. Find the numbers.

Answer 1

Answer:

$\text{First number: }-10, \\\text{Second number: }-4$

Step-by-step explanation:

We can write the following system of equations:

Let the first number be $f$ and the second number be $s$:

$\begin{cases}f+6=s, \\2f-4=6s\end{cases}$

Solving, we get:

$\int\limits^a_b {x} \, dx \begin{cases}f+6=s, \\2f-4=6s\end{cases},\\2f-4=6(f+6),\\2f-4=6f+36,\\-40=4f,\\f=\boxed{-10}$

Solving for $s$:

$f+6=s,\\-10+6=s,\\s=\boxed{-4}$