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olya-2409 [2.1K]
3 years ago
15

What is the value of the expression below?

Mathematics
1 answer:
ioda3 years ago
6 0

Answer:

D

Step-by-step explanation:

4⅜ hope that helps............

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Each student that buys school lunch pays $2.75. The cafeteria typically brings in between $1168.75 and $1438.25. How many studen
Aleksandr [31]
45 times the numerator plus the denominator is most likely going to equal the same amount as if it were doubled.
3 0
3 years ago
MODELING REAL LIFE There are a total of 64 students in a filmmaking club and a yearbook club. The filmmaking club has 14 more st
VashaNatasha [74]

Answer:

The system of linear equations is x + y = 64 and x = y + 14.

Given that,

The total number of students is 64 .

Here we assume the x be the number of students in filmmaking club .

And, y be the number of students in yearbook club.

Based on the above information, the calculation is as follows:

x + y = 64

And,

x = y + 14

Therefore,

We can say that

Number of students in yearbook club = 25

And, the number of students in filmmaking club = 39

3 0
3 years ago
A potato chip company makes potato chips in two flavors, Regular and Salt & Vinegar. Riley is a production manager for the c
tiny-mole [99]

Answer:

(a) H0:μ1=μ2; Ha:μ1≠μ2, which is a two-tailed test.

Step-by-step explanation:

We formulate the

H0: μ1=μ2; null hypothesis that the two means are equal and alternate hypothesis that the two mean are not equal.

Ha:μ1≠μ2 Two tailed test

Test statistic used is

t= x1`-x2` / s√n as the variances are equal and sample size is same

T value for 9 degrees of freedom for two tailed test at α = 0.05 is 2.26

P- value for t test for 9 degrees of freedom is 0.125 from the table.

Hence only a is correct .

4 0
3 years ago
A certain radioactive isotope has leaked into a small stream. Three hundred days after the​ leak, 3% of the original amount of t
sesenic [268]
If the half-life is t, then every t days, the amount of the radioactive isotope will be cut in half.
(1/2)^(number of half-lives) = 3%
number of half-lives = ln(0.03) / ln(0.5)
This gives the number of half-lives as 5.06.
Then 300 days = (5.06)(length of 1 half-life)
length of 1 half-life = 300 / 5.06 = 59.29 days
6 0
4 years ago
Deepak is using blocks to represent the four operation on 8 and 2 witch operation will require the greatest number of blocks
Vadim26 [7]

Answer:

18

Step-by-step explanation:

8 0
3 years ago
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