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In-s [12.5K]
3 years ago
5

? What is the definition of Phyical changes

Physics
2 answers:
dalvyx [7]3 years ago
7 0
Answer : A physical change are changes affecting the form of a chemical substance, but not its chemical composition. Physical changes are used to separate mixtures into their component compounds, but can not usually be used to separate compounds into chemical elements or simpler compounds.
postnew [5]3 years ago
5 0

Answer:

A physical change is the change to the physical properties of an object.

Explanation:

As an example if I take a piece of paper and cut it in half that would be a physical change. Water freezing into ice is also a physical change.

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A person is standing on a scale in an unmoving elevator. The elevator starts to move upwards at 1 m/s squared. Is the scale read
timama [110]

Answer: GREATER

Explanation:when elevator does not move it reads weight of the person . when elevator moves up let apparent weight be F . W acts downwards so net force is F-W

HENCE

F-W =ma

F= ma+W

AS a= 1 m/s^2

F = m (1)+W

HENCE GREATER

7 0
3 years ago
100 points!!!! Will mark brainliest!!!!!!!!
Scorpion4ik [409]

Answer:

Normal Force, Applied force, Gravitational Force, Spring Force

Explanation:

Normal Force so that he does not fall into trampoline, spring because the trampoline spring down when the force goes down, then up putting force upwards, gravitation because of gravity, and applied because of jumping

8 0
3 years ago
Read 2 more answers
A particle of mass m= 2.5 kg has velocity of v = 2 i m/s, when it is at the origin (0,0). Determine the z- component of the angu
melomori [17]

Answer:

please read the answer below

Explanation:

The angular momentum is given by

|\vec{L}|=|\vec{r}\ X \ \vec{p}|=m(rvsin\theta)

By taking into account the angles between the vectors r and v in each case we obtain:

a)

v=(2,0)

r=(0,1)

angle = 90°

L=(2.5kg)(1)(2\frac{m}{s})sin90\°=5.0kg\frac{m}{s}

b)

r=(0,-1)

angle = 90°

L=(2.5kg)(1)(2\frac{m}{s})sin90\°=5.0kg\frac{m}{s}

c)

r=(1,0)

angle = 0°

r and v are parallel

L = 0kgm/s

d)

r=(-1,0)

angle = 180°

r and v are parallel

L = 0kgm/s

e)

r=(1,1)

angle = 45°

L = (2.5kg)(2\frac{m}{s})(\sqrt{2})sin45\°=5kg\frac{m}{s}

f)

r=(-1,1)

angle = 45°

the same as e):

L = 5kgm/s

g)

r=(-1,-1)

angle = 135°

L=(2.5kg)(2\frac{m}{s})(\sqrt{2})sin135\°=5kg\frac{m}{s}

h)

r=(1,-1)

angle = 135°

the same as g):

L = 5kgm/s

hope this helps!!

4 0
4 years ago
What is umax,c, the value of the maximum energy stored in the capacitor during one cycle?
TiliK225 [7]

1) 0.266 H

2) 0.040 J

3) 0.308\Omega

Explanation:

The diagram of the circuit is missing: find it in attachment.

1) What is L, the value of the inductance of the circuit?

For an RLC circuit, the resonant angular frequency is given by:

\omega=\frac{1}{\sqrt{LC}}

where

L is the inductance of the circuit

C is the capacitance of the circuit

In this problem, we have:

\omega=164 rad/s is the angular frequency of the generator, at which the circuit is in resonance

C=140 \mu F = 140\cdot 10^{-6}F is the capacitance

Therefore, solving for L, we find the inductance of the circuit:

L=\frac{1}{\omega^2 C}=\frac{1}{(164)^2(140\cdot 10^{-6})}=0.266 H

2) What is umax,c, the value of the maximum energy stored in the capacitor during one cycle

The maximum energy stored in a capacitor is given by the equation

U=\frac{1}{2}CV^2

where

C is the capacitance of the capacitor

V is the maximum potential difference across the capacitor

Here we have:

C=140 \mu F = 140\cdot 10^{-6}F is the capacitance

V=24 V is the maximum voltage across the capacitor, which is the emf of the generator

Substituting, we find:

U=\frac{1}{2}(140\cdot 10^{-6})(24)^2=0.040 J

3) What is R, the value of the resistance of the circuit?

Here we want to find the resistance of the circuit.

The resistance of the circuit can be found by using Ohm's Law:

V=RI

where

V is the maximum voltage

R is the resistance

I is the maximum current

Here we have:

V = 24 V is the maximum voltage provided by the generator

I = 0.78 A is the maximum current in the circuit

Solving for R, we find the resistance:

R=\frac{V}{I}=\frac{0.24}{0.78}=0.308\Omega

6 0
4 years ago
100 points right here first comr first serve. amos thejonah2016.
Arada [10]

Answer:

Thank you very much!!!

Explanation:

7 0
3 years ago
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