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Stells [14]
4 years ago
13

Suppose 1.4 mol of an ideal gas is taken from a volume of 2.5 m3 to a volume of 1.0 m3 via an isothermal compression at 27°C. (a

) How much energy is transferred as heat during the compression, and (b) is the transfer to or from the gas?
Physics
1 answer:
zysi [14]4 years ago
6 0

Answer:

Part a)

Q = 3198 J

Part b)

It is compression of gas so this is energy transferred to the gas

Explanation:

Part a)

Energy transfer during compression of gas is same as the work done on the gas

In isothermal process work done is given by the equation

W = nRT ln(\frac{V_2}{V_1})

now we know that

n = 1.4 moles

T = 27 degree C = 300 K

V_2 = 2.5 m^3

V_1 = 1 m^3

now we have

W = (1.4)(8.31)(300)(ln\frac{2.5}{1})

Q = 3198 J

Part b)

It is compression of gas so this is energy transferred to the gas

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irakobra [83]

Answer:

minimum length of runway is needed for take off 243.16 m

Explanation:

Given the data in the question;

mass of glider = 700 kg

Resisting force = 3700 N one one glider

Total resisting force on both glider  = 2 × 3700 N = 7400 N

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from the image below, as we consider both gliders as a system

Equation force in x-direction

2ma = T -f

a = T-f / 2m

we substitute

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a = 4600/1400

a = 3.29 m/s²

Now, let Vf be the final speed and Ui = 0 ( as starts from rest )

Vf² = Ui² + 2as

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Vf² = 0 + 2as

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s = Vf² / 2a

given that take of speed for the gliders and the plane is 40 m/s

we substitute

s = (40)² / 2×3.29

s = 1600 / 6.58

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Therefore, minimum length of runway is needed for take off 243.16 m

4 0
3 years ago
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Reil [10]

Answer:

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Explanation:

The force acting on the electron due to the magnetic field is

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Substituting all the numbers into the equation, we find

F=(1.6\cdot 10^{-19}C)(2.5\cdot 10^7 m/s)(4.4 T) sin 90^{\circ}=1.8\cdot 10^{-11} N

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4 years ago
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Norma-Jean [14]

Answer:

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Could there be any options to this one?
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