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Zepler [3.9K]
3 years ago
11

Rules for competitive team sports set which limit?

Physics
2 answers:
Tanya [424]3 years ago
5 0

Answer:

the skill level of players

Explanation:

Yuliya22 [10]3 years ago
3 0

Answer:

Rules for competitive sports are currently set by the number of  players.

Let me know if this helps!

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10 POINTS will mark brainliest if correct
PolarNik [594]
After putting stuff through google and some calculators, I’d say the answer is C.
6 0
4 years ago
An electron (e = 1.6 x 10-19 C) is traveling at 4.00 x 107 m/s due North in a horizontal plane through a point where the earth’s
Irina18 [472]

Answer:

Explanation:

Force on the electron due to magnetic field 's north component will be zero because both velocity of electron and direction of magnetic field are same .

Force due to downward component of magnetic field

= B q v where B is magnetic field , q is charge moving and v is velocity of charge

F = 5 .00 x 10⁻⁵ x 1.6 x 10⁻¹⁹ x 4 x 10⁷

= 32 x 10⁻¹⁷ N

acceleration = F / m where m is mass of electron

= 32 x 10⁻¹⁷ / 9.11 x 10⁻³¹

= 3.5 x 10¹⁴ m/s²

4 0
3 years ago
A disk, initially rotating at 120 rpm, is slowed down with a constant acceleration of magnitude 4 rad s2. If the disk has diamet
andrey2020 [161]

Answer:

Explanation:

given,

ω₁ = 120 rpm

        1 rpm = \dfrac{2\pi }{60} rad/s

         \omega_1 =120\times \dfrac{2\pi }{60} rad/s

                          = 12.56 rad/s

α = - 4 rad/s²

diameter of disk = 20 cm

final angular velocity = 0

t = \dfrac{\omega_f-\omega_i}{\alpha}

t = \dfrac{0-(12.56)}{-4}

t = 3.14 s.

2) \theta = \omega_i t +\dfrac{1}{2} \alpha t^2

              =  12.56\times 3.14 +\dfrac{1}{2}\times (-4)\times 3.14^2

              = 19. 72 radians

3) total angular distance rotated

x = θ R

x = 19.72 × 0.1 = 1.97 m

x = 2 m

3 0
3 years ago
If a 110 kg go-cart traveling at a velocity of 13.41 m/s has a collision with an impulse of 615 Nxs, what is the
mafiozo [28]

Answer:

5.59 m/s

Explanation:

We are given;

Mass = 110 kg

Initial velocity: u = 13.41 m/s

Force = 615 N

Time(t) = 1 s

Now, the formula for force is;

Force = mass x acceleration

Thus;

615 = 110 × acceleration

\Acceleration(a) = 615/110 = 5.591 m/s²

Now, using Newton's first law of motion, we can find acceleration (a). Thus;

v = u + at

v = 13.41 + (5.591 × 1)

v ≈ 19 m/s

So,the change in velocity is;

Final velocity(v) - Initial velocity(u) = 19 - 13.41 = 5.59 m/s

6 0
3 years ago
A car starting from rest accelerates uniformly at 4.3 m/s^2 for 5.0 seconds. How far does the car move?
andreev551 [17]

Answer:

Vf = 21.5 [m/s]

Explanation:

To solve this problem we must use the following kinematics equation:

v_{f}= v_{i} +(a*t)\\

where:

Vf = final velocity [m/s]

Vi = initial velocity = 0

a = aceleration = 4.3 [m/s^2]

t = time = 5 [s]

Now replacing:

Vf = 0 + (4.3*5)

Vf = 21.5 [m/s]

8 0
3 years ago
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