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Musya8 [376]
3 years ago
12

A house is on a hill 10 meters above the base of a 50 meter tall water tower. Calculate the gauge pressure at a tap on the groun

d floor of the house.
Density of water (rho) = 1000 kg/m^3

Acceleration of gravity (g) = 9.8 m/sec^2

Pressure of a fluid column ΔP=ρgΔh

SI units for pressure Pascal = 1 N/m^2 = 1 kg /ms^2


A) 98,000 N/M^2

B) 490,000 N/m^2

C) 588,000 N.m^2

D) 392,000 N/m^2
Engineering
2 answers:
marin [14]3 years ago
7 0

Answer:

Explanation:

Given: Pressure of a fluid column ΔP=ρgΔh

Density of water (ρ) = 1000 kg/m^3

Acceleration of gravity (g) = 9.8 m/sec^2

Δh = difference in height / elevation of water tower and tap

= 50 - 10

= 40

Substitute back into equation:

Pressure = 1000*9.8*40

= 392000 N/m^2

The answer is D.

ankoles [38]3 years ago
5 0

Answer:

Explanation:

Pressure of a fluid column ΔP=ρgΔh

delta h = 50-10 = 40

P = 1000x9.8x40

= 392000

ans is D

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For a metal that has an electrical conductivity of 6.1 × 107 (Ω∙m)–1, what is the resistance of a wire that is 4.3 mm in diamete
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(a) The room-temperature electrical conductivity of a semiconductor specimen is 13 (Ω-m)-1. The hole concentration is known to b
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This parameter, is proportional to the Electric field within the semiconductor, being the proportionality constant, the electrical conductivity of the material, that takes into account the charge carrier concentrations, and the mobility for each type.

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Replacing by the given values, and the value of q (charge of an electron), we can get the only unknown that remains, ne , as follows:

ne =( σ – (q . np . µp)) / q µe = (13 (Ω.m)-1 – (1.6E-19) coul(4.0E+20) m-3.0.18) m2/V-s /( (1.6E-19).0.38) coul.m2/V-s

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