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Softa [21]
3 years ago
12

A liquid mixture containing 0.45 mol fraction of heptane and 0.55 mole fraction ethyl benzene is fed as saturated vapor to a dis

tillation column at a flow rate of 200 kgmol/h for product separation. The distillation operates at 1 atm (absolute). The recovery of heptane (to the distillate product) is 95% and the required heptane purity in the distillate is 0.98 (mole fraction). Calculate the following:
a. The distillate and bottom flowrates
b. The minimum reflux ratio
c. The minimum number of stages
d. The number of stages at a reflux ratio of 1.5Rmin
Engineering
1 answer:
riadik2000 [5.3K]3 years ago
3 0
I think it’s c but I’m now sure so don’t count on it
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prohojiy [21]

Answer:

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Explanation:

7 0
2 years ago
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A cylindrical specimen of a hypothetical metal alloy is stressed in compression. If its original and final diameters are 30.00 a
IrinaVladis [17]

Answer:

The original length of the specimen l_{o} = 104.7 mm

Explanation:

Original diameter d_{o} = 30 mm

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Change in diameter Δd = 0.04 mm

Final length l_{1} = 105.20 mm

Elastic modulus E = 65.5 G pa = 65.5 × 10^{3} M pa

Shear modulus G = 25.4 G pa = 25.4 × 10^{3} M pa

We know that the relation between the shear modulus & elastic modulus is given by

G = \frac{E}{2(1 + \mu)}

25.5 = \frac{65.5}{2 (1 + \mu)}

\mu = 0.28

This is the value of possion's ratio.

We know that the possion's ratio is given by

\mu = \frac{\frac{0.04}{30} }{\frac{change \ in \ length}{l_{o} } }

{\frac{change \ in \ length}{l_{o} } = \frac{\frac{0.04}{30} }{0.28}

{\frac{change \ in \ length}{l_{o} } = 0.00476

\frac{l_{1} - l_{o}  }{l_{o}  } = 0.00476

\frac{l_{1} }{l_{o} } = 1.00476

Final length l_{o} = 105.2 m

Original length

l_{o} = \frac{105.2}{1.00476}

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5 0
3 years ago
Adding new equipment or processes may require changes to the PPE requirements for
Yuki888 [10]
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2 years ago
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Steam enters an adiabatic condenser (heat exchanger) at a mass flow rate of 5.55 kg/s where it condensed to saturated liquid wat
Evgen [1.6K]

Answer:

The minimum mass flow rate will be "330 kg/s".

Explanation:

Given:

For steam,

m_{s}=5.55 \ kg/s

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For water,

\Delta T=10^{\circ}C

(Cp)_{w}=4.184 \ kJ/kg^{\circ}C

They add energy efficiency as condenser becomes adiabatic, with total mass flow rate of minimal vapor,

⇒  m_{s}\times (\Delta h)=M_{w}\times(Cp)_{w}\times \Delta T

On putting the estimated values, we get

⇒  5.55\times 2491=M_{w}\times 4.184\times 10\\

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Read more about fuel injection engines at; brainly.com/question/4561445

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