Block B starts from rest and moves downward with a constant acceleration. Knowing that after slider block A has moved 400 mm its
1 answer:
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Answer:
The system can be described by a convolution
Explanation:
Thinking process:
If we consider a discrete input to a linear time-invariant system, then the system will be periodic with respect to the period, say N. This therefore, means that the output must also be periodic. The proof is as follows:
The LTI system can be written for the system where:
y (n+N) = ∑
= ∑
From the proof, it turns out that y(y + N) = y(n) for any value of n, then the output will be the periodic with the period N.
Answer:
The simplest differential form of Fick's flux equation for water vapor is
Explanation:
Fick's law has to do with the density of the particles is proportional to their concentration gradient. For this question some assumptions will be taken into account:
-The pipe is considered to be very long and diffusion only occurs in the r direction.
-The reaction is not homogeneous, therefore RA = 0
-The concentration of the component A is constant
-No mixing, only diffusion
Due to the complexity of the terms used in solving the Fick equation, the solution is found in the attached file.
Answer:
<em>a) 4.51 lbf-s^2/ft</em>
<em>b) 65.8 kg</em>
<em>c) 645 N</em>
<em>d) 23.8 lb</em>
<em>e) 65.8 kg</em>
<em></em>
Explanation:
Weight of the man on Earth = 145 lb
a) Mass in slug is...
32.174 pound = 1 slug
145 pound = slug
= 145/32.174 = <em>4.51 lbf-s^2/ft</em>
b) Mass in kg is...
2.205 pounds = 1 kg
145 pounds = kg
= 145/2.205 = <em>65.8 kg</em>
c) Weight in Newton = mg
where
m is mass in kg
g is acceleration due to gravity on Earth = 9.81 m/s^2
Weight in Newton = 65.8 x 9.81 = <em>645 N</em>
d) If on the moon with acceleration due to gravity of 5.30 ft/s^2,
1 m/s^2 = 3.2808 ft/s^2
m/s^2 = 5.30 ft/s^2
= 5.30/3.2808 = 1.6155 m/s^2
weight in Newton = mg = 65.8 x 1.6155 = 106
weight in pounds = 106/4.448 = <em>23.8 lb</em>
e) The mass of the man does not change on the moon. It will therefore have the same value as his mass here on Earth
mass on the moon = <em>65.8 kg</em>