Y =ax² + bx +c
1) Point (0,7)
7 = a*0² +b*0 +c
c = 7
y=ax² + bx + 7
2) Point (1,4)
4=a*1² + b*1 + 7, ----> 4 = a +b + 7, ------>
a+b= - 3
3) Point (2, 5)
5=a*2² + b*2 + 7, ----> 5=4a+2b +7,---> -2=4a+2b, ---->
-1=2a + b
4)
a+b= - 3, ----> b= -3 - a (substitute in the second equation)
2a+b= -1
2a - 3 - a = -1, ----> a - 3 = -1,
a =2
5) a+b= - 3
2 + b = -3
b = -5
y=2x² - 5x + 7
Answer:
The coterminal angles are : 270° , -450°
sketched angle is in third quadrant
Step-by-step explanation:
The sketch of the angle in standard position is attached below
The coterminal angles :
- 90 + 360 = 270°
-90 - 360 = -450°
Quadrant of the angle( -90° ) = Third quadrant
Answer:
$7
Step-by-step explanation:
Your two equations are ...
Double the second equation and subtract the first:
2(2s +4t) -(4s +6t) = 2(42) -(70)
2t = 14 . . . . . simplify
t = 7 . . . . . . . divide by 2
The cost of each tie is $7.
14 + {-2 + 3[1 + 3(-6-2)]}
14 + { -2 + 3[1 + 3(-8)]}
14 + { -2 + 3[1 - 24]}
14 + { -2 + 3[-23]}
14 + {-2 - 69}
14 + {-71}
14 - 71
- 57 <==
Answer:
21/22 = repeating
60/120 = terminating
56/72 = repeating
11/121 = repeating
Step-by-step explanation:
i just know. fight me.