Someone please help with these linear equations problems.
1 answer:
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Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Answer:
A rational expression that has the nonpermissible values and
is
.
Step-by-step explanation:
A rational expression has a nonpermissible value when for a given value of , the denominator is equal to zero. In addition, we assume that both numerator and denominator are represented by polynomials, such that:
(1)
Then, the factorized form of must be:
(2)
If we know that , then the rational expression is:
(3)
A rational expression that has the nonpermissible values and
is
.