The student does a work of 500 Newton meter on the box.
Step-by-step explanation:
Given,
Weight of box of books = force = 200 N
Distance the box is lifted = 2.5 m
Work done = Force * distance
Work done = 
Work done = 500 Newton-meter
Newton meter is same as Joule.
Work done = 500 Joules
The student does a work of 500 Newton meter on the box.
Keywords: multiplication, work done
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Answer:
1/2
Step-by-step explanation:
<u>Hello:</u>
<u />
<u>Okay, this problem should be taken in a series of steps</u>:
<u>What is the slope's formula?</u>
- (x₁,y₁) -- first point
- (x₂,y₂) -- second point
<u>Okay, now let's use this knowledge</u>
10. (5,-19) and (-5,21)
11. (12,1) and (12, -1)
12. (8,7) and (4,7)
<u>Answer:</u>
- Question 10: -4
- Question 11: undefined
- Question 12: 0
Hopefully that helps!
Answer:
I think the answer would be 22.15 but I'm not really sure.
The picture in the attached figure
we know that
the area of the shaded region is equal to
(2/3)*[area of the circle - the area of the triangle]
step 1Find the area of a circle Ac
Ac = π r²
Ac = π (6)²
Ac = 113.10 units²
step 2find the area of the triangle At
The triangle is an equilateral triangle with angles on each corner equal to 60 degrees. Meanwhile,
the 3 angles at the center is 120 degrees each since a circle is 360 degree.
We know that the radius (line from centerpoint to corner) is equivalent to 6.
Using the cosine law,
we can calculate for the length of one side.
s² = 6^ + 6² – 2 (6) (6) cos 120
s² = 108
s = 10.4 units
Since this is an equilateral triangle, therefore, all sides are equal.
The area for this is:
At = (sqrt3 / 4) * s²
At = 46.77 units²
step 3the area of the shaded region=(2/3)*[area of the circle - the area of the triangle]
the area of the shaded region=(2/3)*[113.10-46.77]------> 44.22 units²
therefore
the answer isthe area of the shaded region is 44.22 units²
