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Temka [501]
3 years ago
7

11b-12<-100

Mathematics
2 answers:
ruslelena [56]3 years ago
4 0

Answer:

ok wait which symbol? this (<)?

well it should stay the same since -100 is greater than the 11b-12

LHS=RHS

11b÷11b b must cancell b also do the same on -12. -12÷11 will give u a lesser value compared to -100

prove me wrong

Arturiano [62]3 years ago
3 0

Answer

b<-8

It's going to stay the same. when you are doing inequalities, you only flip the sign if you are driving by a negative number. for this question you are not going to divide by a negative number, so the sign stays the same. let's get to the problem.

First, rewrite the problem.

11b-12<-100

secondly, add 12 to both sides and subtract.

11b-12<-100

+12. +12

thirdly, your equation is going to be like this.

11b<-88

next, divide both sides by 11 and your answer will be

b<-8

since 11b was positive, you will not change the sign but if 11b was going to be a negative number, then you were going to change the sign to >. hope this helps.

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Given the inequalities:4

\begin{gathered} 4x+3>0 \\ 9x-5

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Substitute 8 for x in each inequality and check whether it satisfies the inequality.

Consider 4x + 3 > 0.

4\cdot8+3=35>0

So, x = 8 satisfies the inequality 4x + 3 > 0.

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9\cdot8-5=67

So, x = 8 satisfies the inequality 9x - 5 < 100.

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So, x = 8 not satisfies the inequality.

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