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Temka [501]
3 years ago
7

11b-12<-100

Mathematics
2 answers:
ruslelena [56]3 years ago
4 0

Answer:

ok wait which symbol? this (<)?

well it should stay the same since -100 is greater than the 11b-12

LHS=RHS

11b÷11b b must cancell b also do the same on -12. -12÷11 will give u a lesser value compared to -100

prove me wrong

Arturiano [62]3 years ago
3 0

Answer

b<-8

It's going to stay the same. when you are doing inequalities, you only flip the sign if you are driving by a negative number. for this question you are not going to divide by a negative number, so the sign stays the same. let's get to the problem.

First, rewrite the problem.

11b-12<-100

secondly, add 12 to both sides and subtract.

11b-12<-100

+12. +12

thirdly, your equation is going to be like this.

11b<-88

next, divide both sides by 11 and your answer will be

b<-8

since 11b was positive, you will not change the sign but if 11b was going to be a negative number, then you were going to change the sign to >. hope this helps.

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What is the percent decrease from 60 to 39?
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The number of pollinated flowers as a function of time in days can be represented by the function. f(x)
ratelena [41]

The average increase in the number of flowers pollinated per day between days 4 and 10 is <u>39</u>, given that the number of pollinated flowers as a function of time in days can be represented by the function f(x) = (3)^{\frac{x}{2} }.

In the question, we are asked for the average increase in the number of flowers pollinated per day between days 4 and 10, given that the number of pollinated flowers as a function of time in days can be represented by the function f(x) = (3)^{\frac{x}{2} }.

To find the average increase in the number of flowers pollinated per day between days 4 and 10, we use the formula {f(10) - f(4)}/{10 - 4}.

First, we find the value of the function f(x) = (3)^{\frac{x}{2} }, for f(10) and f(4).

f(x) = (3)^{\frac{x}{2} }\\\Rightarrow f(10) = (3)^{\frac{10}{2} }\\\Rightarrow f(10) = 3^5 = 243

f(x) = (3)^{\frac{x}{2} }\\\Rightarrow f(4) = (3)^{\frac{4}{2} }\\\Rightarrow f(10) = 3^2 = 9

Thus, the average increase

= {f(10) - f(4)}/{10 - 4},

= (243 - 9)/(10 - 4),

= 234/6

= 39.

Thus, the average increase in the number of flowers pollinated per day between days 4 and 10 is <u>39</u>, given that the number of pollinated flowers as a function of time in days can be represented by the function f(x) = (3)^{\frac{x}{2} }.

Learn more about the average increase in a function at

brainly.com/question/7590517

#SPJ4

For complete question, refer to the attachment.

8 0
1 year ago
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