PLEASE HELP I really need Help Im offering 100 Points so please help me
2 answers:
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Answer:
66 + 1 ( not fully shaded ) squares will be shaded.
66.67% region will be shaded
Step-by-step explanation:
It is given that Marks uses a grid to model percent equivalent of .
Let us assume that Mark uses a model containing 100 grids.
Now, as the grids are divided into region equivalent to i.e. it is divided into 3 parts.
Moreover, 2 out of those 3 parts will be shaded.
As,
i.e. =66.67%
So, it gives us that 66 squares in the grid will be fully shaded and one will not be fully shaded.
Hence, 66 + 1 ( not fully shaded ) squares will be shaded and in percent, 66.67% of the region will be shaded.
Answer:
(a) 0.119
(b) 0.1699
Solution:
As per the question:
Mean of the emission, million ponds/day
Standard deviation, million ponds/day
Now,
(a) The probability for the water pollution to be at least 15 million pounds/day:
= 1 - P(Z < 1.178)
Using the Z score table:
= 1 - 0.881 = 0.119
The required probability is 0.119
(b) The probability when the water pollution is in between 6.2 and 9.3 million pounds/day:
P(Z < - 0.86) - P(Z < - 1.96)
Now, using teh Z score table:
0.1949 - 0.025 = 0.1699
Answer:
Here you go, I think
Step-by-step explanation:
