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bogdanovich [222]
3 years ago
15

Last question for the night.

Mathematics
1 answer:
horsena [70]3 years ago
4 0

Answer:

third option

Step-by-step explanation:

\frac{16 {x}^{2} }{4x + 24}  \div   \frac{8 {x}^{2}  - 40x}{ {x}^{2}  - 36}   \\  =  \frac{16 {x}^{2} }{4(x + 6)}  \times  \frac{(x + 6)(x - 6)}{8x(x - 5)} \\  =  \frac{16 {x}^{2} }{4}  \times  \frac{x  - 6}{8x(x - 5)}  \\  =  \frac{x}{1}   \times  \frac{x - 6}{2(x - 5)}  \\  =  \frac{x(x + 6)}{2x - 10}

hope it helped

pls mark BRAINLIEST

thanks

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Krya is playing a card game. Black cards are worth points while red cards take points away. What is her score if she has a black
Nitella [24]

Answer:

her score would be -22

Step-by-step explanation:

20-42=-22

8 0
3 years ago
For the function defined by:
Eva8 [605]

The first function is represented by the green line, while the second is represented by the orange line

<h3>What are piecewise functions?</h3>

Piecewise functions are functions that have at least 2 sub functions, each of which have different intervals

The function is defined by

f(x) = \left \{ {{x^2,\ x\le1} \atop {2x + 1,\ x > 1}} \right.

<h3>(a) Graph the first function</h3>

The first function in f(x) is defined by

f(x) = x^2, \ x \le 1

See attachment for the graph of the first function

<h3>(b) Graph the second function</h3>

The second function in f(x) is defined by

f(x) = 2x + 1, \ x > 1

See attachment for the graph of the second function

Read more about piecewise functions at:

brainly.com/question/18859540

7 0
2 years ago
What is the resistance of a 1.00X10^2 -Ω , a 2.50-kΩ , and a 4.00-k Ω resistor connected in parallel?
Andreas93 [3]

Answer:

Therefore, the total Resistance:  R = 93.9 Ω

Step-by-step explanation:

Given

R₁ = 1 × 10²

R₂ = 2.5 kΩ = 2.5 × 10³ Ω

R₃ = 4  kΩ = 4 × 10³ Ω

Given that the given resisters are connected parallel, so using the formula to calculate the total Resistance R:

\frac{1}{R}\:=\:\frac{1}{R_1}\:+\:\frac{1}{R_2}+\frac{1}{R_3}

susbtituting R₁ = 1 × 10², R₂ = 2.5 × 10³ Ω, and R₃ = 4 × 10³ Ω

\frac{1}{R}=\frac{1}{1\times \:10^2}+\frac{1}{2.5\times \:10^3}+\frac{1}{4\times \:10^3}

Multiply by LCM of R, 100, 2500, and 4000:   20000 R

\frac{1}{R}\cdot \:20000R=\frac{1}{1\cdot \:10^2}\cdot \:20000R+\frac{1}{2.5\cdot \:10^3}\cdot \:20000R+\frac{1}{4\cdot \:10^3}\cdot \:20000R

simplify

20000=213R

Switch sides

213R=20000

Divide both sides by 213

\frac{213R}{213}=\frac{20000}{213}

Simplify

R=\frac{20000}{213}

R = 93.9 Ω

Therefore, the total Resistance:  R = 93.9 Ω

4 0
3 years ago
Use binomial expansion to solve each exercise. (a) Find the coefficient of xy19 in (3x − 2y) 20.(b) Give a formula for the coeff
pishuonlain [190]

9514 1404 393

Answer:

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__

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For some exponent k of x, the value of p will be ...

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C

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