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harkovskaia [24]

3 years ago

10

You are attending a college night. There is a different school in each classroom. Of the schools in attendance 30% had a sports

program you are interested in, 40% have an academic program you are interested in and 60% have either a sports or academic program you are interested in. If you walk into a room at random, what is the probability that the school has both a sports and academic program you are interested in?
a. 0.]20
b. 0.10
c. 0.70
d. 0.30
(NO LINKS! I WILL GIVE BRAINLIEST TO ANSWER!)

1 answer:

elixir [45]3 years ago

7 0

Answer:

0.10

Step-by-step explanation:

Technically it's 0.12 but I only say this because they rounded by from 58 to 60 in their question

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Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.

Tems11 [23]

Answer and explanation:

To find : Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.

Solution :

The area of the square is given by,

$A=s^2$ where s is the side length.

We know, $1 \text{ hectare}=10,000\ m^2$

1) The area of square plot is 7 hectare.

Area in meter square is $A=7\times 10000=70000\ m^2$

Substitute the value in the formula,

$70000=s^2$

$\sqrt{70000}=s$

$264.57=s$

Side nearest to 1/10th meter is 264.8 meter.

2) The area of square plot is 12 hectare.

Area in meter square is $A=12\times 10000=120000\ m^2$

Substitute the value in the formula,

$120000=s^2$

$\sqrt{120000}=s$

$346.41=s$

Side nearest to 1/10th meter is 346.4 meter.

3) The area of square plot is 30 hectare.

Area in meter square is $A=30\times 10000=300000\ m^2$

Substitute the value in the formula,

$300000=s^2$

$\sqrt{300000}=s$

$547.72=s$

Side nearest to 1/10th meter is 547.7 meter.

5 0

3 years ago

Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ

In-s [12.5K]

PART A

The equation of the parabola in vertex form is given by the formula,

$y - k = a {(x - h)}^{2}$

where

$(h,k)=(1,-2)$

is the vertex of the parabola.

We substitute these values to obtain,

$y + 2 = a {(x - 1)}^{2}$

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.

$6 + 2 = a {(3 - 1)}^{2}$

$8= a {(2)}^{2}$

$8=4a$

$a = 2$
Hence the equation of the parabola in vertex form is

$y + 2 = 2 {(x - 1)}^{2}$

PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

$y + 2 = 2{(x - 1)}^{2}$

This implies that

$y + 2 = 2(x - 1)(x - 1)$

We expand to obtain,

$y + 2 = 2( {x}^{2} - 2x + 1)$

This will give us,

$y + 2 = 2 {x}^{2} - 4x + 2$

$y = {x}^{2} - 4x$

This equation is now in the form,

$y = a {x}^{2} + bx + c$
where

$a=1,b=-4,c=0$

This is the standard form

7 0

3 years ago

Y=4x-9 complete the missing value in the solution to the equqtion (3, )

julsineya [31]

Answer:

3

Step-by-step explanation:

The question gives you the x coordinate, so plug in x with 3.

y=4(3)-9

y=12-9=3

y=3

(3,3)

6 0

3 years ago

Read 2 more answers

What is the rang y=-x2 - 2x + 3?

Damm [24]

This is a downward facing parabola, so its range comes in the form

$(-\infty, m)$ where m is the y coordinate of the vertex of the parabola.

We can find the x coordinate of the vertex using

$x=-\dfrac{b}{2a}=-\dfrac{-2}{-2}=-1$

And if we plug -1 in the equation we get the y coordinate of the vertex:

$y=-(-1)^2-2(-1)+3 = -1+2+3=4$

So, the range is the interval

$(-\infty, 4)$

5 0

4 years ago

Two positive integers have a product of 200.

sattari [20]

Since 200 is a constant, of x, move 200 out of the integral. 200x+c. Constant is a fixed value that does not change.

IF YOU LIKE MY ANSWER PLS GIVE ME BRAINLIEST!!

3 0

3 years ago