Question

As runners in a marathon go by, volunteers hand them small cone shaped cups of water. The cups have the dimensions shown. Abigail sloshes 23\dfrac2332​start fraction, 2, divided by, 3, end fraction of the water out of her cup before she gets a chance to drink any.

Answer 1

Answer:

$8 \pi$

Step-by-step explanation:

The computation of the volume of water remaining is shown below:

The volume of the cone is

$\pi r^2 \frac{h}{3}\\\\\pi \times 3^2 \times \frac{8}{3} \\\\\frac{72}{3} \pi \\\\24 \pi$

Now since it is two-third so the remaining is one -third

$= 24 \pi \times \frac{1}{3}$

$= 8 \pi$

hence, the volume of water remaining is $8 \pi$