Question

(Affgfbwg I’m struggling) Find the value of x in the isosceles triangle shown below

Answer 1

Answer:

B

Step-by-step explanation:

The line from the vertex to the base is a perpendicular bisector and divides the isosceles triangle into 2 right triangles with hypotenuse x

Using Pythagoras' identity in either of the 2 right triangles, then

x² = 12² + 5² = 144 + 25 = 169 ( take the square root of both sides )

x = $\sqrt{169}$ = 13 → B