(Affgfbwg I’m struggling) Find the value of x in the isosceles triangle shown below
1 answer:
Answer:
B
Step-by-step explanation:
The line from the vertex to the base is a perpendicular bisector and divides the isosceles triangle into 2 right triangles with hypotenuse x
Using Pythagoras' identity in either of the 2 right triangles, then
x² = 12² + 5² = 144 + 25 = 169 ( take the square root of both sides )
x = = 13 → B
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My apologies on answering late...
Same situation as the previous problem, but this time, all you need to do is state the degree of the angle instead of just providing the angle itself.
ΔABC ≅ ΔDEF
Now, we can see that ∠C ≅ ∠F. Using this information, we can find ∠C on the first triangle ( which is ° ).
Since ∠C ≅ ∠F,
m∠F is °.
Hope I caught your question in time!
Have a good one! If you need anymore help, let me know.