(Affgfbwg I’m struggling) Find the value of x in the isosceles triangle shown below

Mathematics

1 answer:

Nady [450]2 years ago

7 0

Answer:

Step-by-step explanation:

The line from the vertex to the base is a perpendicular bisector and divides the isosceles triangle into 2 right triangles with hypotenuse x

Using Pythagoras' identity in either of the 2 right triangles, then

x² = 12² + 5² = 144 + 25 = 169 ( take the square root of both sides )

x = $\sqrt{169}$ = 13 → B

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Mamont248 [21]

For this case, the first thing to do is to model the rectangular sandbox as a rectangular prism.

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Where,

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l: length
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Therefore, replacing values we have:

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Answer:

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8 0

2 years ago

X(x+9)=0 x=? What does x have to be for the answer to be 0?

yaroslaw [1]

when we solve the equation it will become
x² + 9x= 0
now here a = 1 , b = 9 and c = 0
by using quaderatic formula
x = -b +,-√b ²- 4ac / 2a ( 2a is divided by all terms )
by putting values
x = - 9 +,- √81 / 2(1) ( √81 = 9)
x = -9 + 9 / 2 and x = -9 -9 /2
x = 0 and x = -18 /2 = -9
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2 years ago

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1. What is the radius of the circle below? 14 cm

alekssr [168]

Answer:

the radius is 7

Step-by-step explanation:

the full lenght is the circumference and a raduis is half of that, therefore 7

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2 years ago

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