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3 years ago

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After filling a gas tank the odometer read 27,8295After the next filling it read 28,1760. It took 17.5 gal to fill the tank How

many miles per gallon did the driver get?

1 answer:

aivan3 [116]3 years ago

7 0

Answer:

198 mpg

Step-by-step explanation

28,1760-27,8295 = 3465 miles

3465miles/17.5gal = 198 mpg

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What is 174 dived by 6 and how u solved it

Minchanka [31]

Answer:

Step-by-step explanation:

187 divided by 7 is 6.5

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3 years ago

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Quadratic 6X2 + 5X = -7

poizon [28]

Ok, so here your being asked to solve 6x2<span> + 5x = -7

The procedure that I did was using this formula it led me to get the following:
</span>Using the formula:

x = -(-5) ± √(-5)² - 4(6)(-6)/ 2(6)
x = 5 ± √ 25 + 144 / 12
x = 5 ± √ 169 / 12
x = 5 ± 13/12

x1 = 5 + 13/12
x1 = 18/12
x1 = 3/2

x2 = 5 - 13/12
x2 = -8/12
<span> x2 = - 2/3

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3 years ago

How many terms dose 4x + 8y -1

solniwko [45]

3 terms 4x,8y and -1

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2 years ago

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Please help!!!! BRAINLIEST for whoever is correct!! What is the difference of the rational expressions below?

Nostrana [21]

Answer:

<h2> $\frac{3x + 25}{5 {x}^{2} }$ </h2>

Step-by-step explanation:

$\frac{x + 5}{ {x}^{2} } - \frac{2}{5x}$

Write all the numbers above the least common denominator ${5x}^{2}$

$\frac{5(x + 5) - 2x}{5 {x}^{2} }$

Distribute 5 through the parentheses

$\frac{5x + 25 - 2x}{5 {x}^{2} }$

Collect like terms

$\frac{3x + 25}{5 {x}^{2} }$

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3 years ago

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Use calculus to find the first order conditions. Use solver then to solve the first order conditions. Show your work for the fir

DaniilM [7]

The values of x and y are 70/22 and 30/22 respectively by using the first-order condition of differential calculus.

<h3>What is the first-order condition in differential calculus?</h3>

A first-order differential equation is represented by the equation $\mathbf{ \dfrac{dy}{dx} =f (x,y) }$ with 2 variables x & y, including its function f(x,y) specified on a xy-plane.

Given that:

$\mathbf{f(x,y) =-22x^2+22xy-11y^2+110x-40y-23}$

Let us first differentiate the above equation with respect to x, we have:

$\mathbf{\dfrac{\partial f(x,y) }{\partial x} = -44x +22y -0+110-0-0=0}$

$\mathbf{\implies -44x +22y+110=0}$ (multiply by -1)

44x - 22y = 110 ------ (equation 1)

Now, differentiating with respect to y, we have:

$\mathbf{\dfrac{\partial f(x,y) }{\partial y} =0 +22x-22y +0-40-0=0}$

$\mathbf{\implies 22x-22y -40=0}$

22x - 22y = 40 ----- (equation 2)

Now, we have a system of equations:

44x - 22y = 110

- ---- ( subtracting equation 2 from 1; elimination method)

<u> 22x - 22y = 40 </u>

<u>22x + 0 = 70 </u>

<u />

x = 70/22

Replacing the value of x into equation (1), we have:

44x - 22y = 110

44(70/22) - 22y = 110

140 - 22y = 110

140 - 110 = 22y

30 = 22y

y = 30/22

Learn more about the first-order conditions in differential calculus here;

brainly.com/question/14528981

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1 year ago