Can someone plz help me ?

Function or no? i just need a simple yes or no. ;-;

ryzh [129]

Answer:

yes

Step-by-step explanation:

6 0

3 years ago

If your starting salary is $35,000 and you receive a 6% increase at the end of every year, what is the total amount, in dollars,

aksik [14]

The starting salary is $35,000.

Salary is increased by 6% at the end of every year.

Nos of years worked = 16 years

Total salary earned in 16 years is given by An * (( 1+i )^n - 1 ) / i

Where, An = Present Salary = $35000

i = Increase in salary per year = 6% = 0.06

n = number of years = 16

= 35000 * ( 1.06 ^16 - 1 ) / .06

= 35000 * ( 2.54035 - 1 ) / .06

= 35000 * 1.54035 / .06

= 898538

Total earnings in 16 years is $ 898538

5 0

3 years ago

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 400 babies were born, a

Masja [62]

Answer:

(a) 99% confidence interval for the percentage of girls born is [0.804 , 0.896].

(b) Yes, the proportion of girls is significantly different from 0.50.

Step-by-step explanation:

We are given that a clinical trial tests a method designed to increase the probability of conceiving a girl.

In the study 400 babies were born, and 340 of them were girls.

(a) Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of girls born = $\frac{340}{400}$ = 0.85

n = sample of babies = 400

p = population percentage of girls born

Here for constructing 99% confidence interval we have used One-sample z proportion statistics.

So, 99% confidence interval for the population proportion, p is ;

P(-2.58 < N(0,1) < 2.58) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.58 & 2.58}

P(-2.58 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.58) = 0.99

P( $-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.85-2.58 \times {\sqrt{\frac{0.85(1-0.85)}{400} } }$ , $0.85+2.58 \times {\sqrt{\frac{0.85(1-0.85)}{400} } }$ ]

= [0.804 , 0.896]

Therefore, 99% confidence interval for the percentage of girls born is [0.804 , 0.896].

(b) Let p = population proportion of girls born.

So, Null Hypothesis, $H_0$ : p = 0.50 {means that the proportion of girls is equal to 0.50}

Alternate Hypothesis, $H_A$ : p $\neq$ 0.50 {means that the proportion of girls is significantly different from 0.50}

The test statistics that will be used here is One-sample z proportion test statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of girls born = $\frac{340}{400}$ = 0.85

n = sample of babies = 400

So, the test statistics = $\frac{0.85-0.50}{\sqrt{\frac{0.85(1-0.85)}{400} } }$

= 19.604

Now, at 0.01 significance level, the z table gives critical value of 2.3263 for right tailed test. Since our test statistics is way more than the critical value of z as 19.604 > 2.3263, so we have sufficient evidence to reject our null hypothesis due to which we reject our null hypothesis.

Therefore, we conclude that the proportion of girls is significantly different from 0.50.

8 0

3 years ago

What set or sets of real numbers does -√16 belong to?

Sati [7]

Answer:

Step-by-step explanation:

Well the square root of 16 can be simplified to 4, which can be represented as a fraction: 4/1, so it's not irrational, but rather rational.

Whole numbers are similar to integers, and natural numbers, the only difference is integers includes all real numbers, which do not have a decimal value. So this includes negative numbers, zero, and positive numbers.

Whole numbers include all real numbers, which do not have a decimal value, and are greater than or equal to zero, or in other words, not negative.

Natural numbers include all real numbers, which do not have a decimal value, and are greater than zero, or in other words, positive numbers.

So this number is a integer, and rational number. (since the negative number in front of the radical)

4 0

2 years ago

Read 2 more answers

Mary runs 3.2 miles every 10 minutes. At this rate, how many miles does she run in an hour?

Roman55 [17]

Answer:

19.2 miles

Step-by-step explanation:

Because you already have ran 3.2 every 10 minutes and there is 60 minutes in a hour so you will have to multiply 3.2 x 6 = 19.2

8 0

4 years ago

Read 2 more answers