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katrin [286]
3 years ago
14

HELP Between steps 2 and 3, the chemical energy in the coal is converted to

Chemistry
2 answers:
xxTIMURxx [149]3 years ago
5 0

Answer:

Transitional Energy ......

Explanation:

Hope this helps..................................

emmasim [6.3K]3 years ago
4 0

Answer:

heat energy!!!

Explanation:

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Calculate Δ H o for the reaction. CH3OH + HCl → CH3Cl + H2O answer is in kJ/mol .
Nimfa-mama [501]

Answer:

\Delta H=-28.08 \frac{kJ}{mol}

Explanation:

Hello,

This types of reactions are likely to be carried out in gaseous phase as it is easier to induce reactions, therefore, for us to compute the change in the enthalpy of this reaction we should write the formation enthalpy of gaseous methanol, hydrogen chloride, methyl chloride and water as -205.1, -92.3, -83.68 and -241.8 kJ/mol respectively. Then, the reaction enthalpy for this reaction is:

\Delta H=\Delta _fH_{CH_3Cl}+\Delta _fH_{H_2O}-\Delta _fH_{CH_3OH}-\Delta _fH_{HCl}\\\\\Delta H=-83.68\frac{kJ}{mol}-241.8\frac{kJ}{mol}-(-205.1\frac{kJ}{mol})-(-92.3\frac{kJ}{mol} )\\\\\Delta H=-28.08 \frac{kJ}{mol}

Which accounts for an exothermic chemical reaction.

Regards.

7 0
4 years ago
Is one quarter the size of earth, has no moons, and has an almost non-existent atmosphere
PIT_PIT [208]

For the answer to the question above,
If you mean planet, that would be Mercury. There are other objects in our solar system that could fit the criteria. 
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7 0
3 years ago
Read 2 more answers
How many moles of KCl will be formed from 2.73 grams of KClO3
Art [367]

Answer:

0.0222 mol KCl

Explanation:

2 KClO3 (s)   2 KCl (s) + 3 O2 (g)

2.73 g                x mol

x g KCl = 2.73 g KClO3 x[ (1 mol KClO3)/ (122.5 g KClO3) ] x [(2 mol KCl)/ (2 mol KClO3)]

x g KCl = 0.0222 mol KCl

8 0
3 years ago
What is the molarity of a solution containing 400g cuso4 in 4.00 l of solution
Murrr4er [49]
Calculation- 
400gCuSo4
----------------  ] faction 2.5 over 4 which EQUALS .625MCuSO4 in decimal form
           1
8 0
3 years ago
All of the above
Natalka [10]
The plants without any fertiliser could be the control, to see what the change in the independent variable (fertiliser) does to the growth of the plant (dependant variable).

Hope that helps.
8 0
3 years ago
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