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katrin2010 [14]
4 years ago
12

Which situations make use of interactive multimedia and which do not?

Chemistry
1 answer:
xxMikexx [17]4 years ago
4 0
Fred is using interactive for sure. It requires a response from you, not just looking, watching, or listening.
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Which of the following affects the rate of a chemical reaction?
butalik [34]
D. A ll of the above. catalyst reduces the activation energy thereby making the reaction faster. an increase in temperature  increases the kinetic energy and no of collisions making reaction faster for an endothermic reaction while decrease in temperature favors an exothermic reaction.
increase in concentration increases the molecules reacting so the reaction is faster and vice versa.
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4 years ago
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Delvig [45]
Bestie since it’s Cl2, put 2 next to KCl. That means you need to 2 moles of K, so put 2 next to KI. That’s it
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3 years ago
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Gasoline has an octane number of 70.
mariarad [96]
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5 0
4 years ago
What is the sum of 3.41 + 5.3 +8.2010?
PolarNik [594]

Answer:

\frac{16911}{1000} ​= 16.91100

Explanation:

Adding up the two equivalent fractions

871 • 10 + 8201   16911

____________________ = 16.91100

1000                  1000

8 0
4 years ago
Hydrogen iodide decomposes slowly to H2 and I2 at 600 K. The reaction is second order in HI, and the rate constant is 9.7×10−6M−
Lady bird [3.3K]

Answer : The molarity after a reaction time of 5.00 days is, 0.109 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 9.7\times 10^{-6}M^{-1}s^{-1}

t = time taken  = 5.00 days

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.110 M

Now put all the given values in above equation, we get:

9.7\times 10^{-6}=\frac{1}{5.00}\left (\frac{1}{[A]}-\frac{1}{(0.110)}\right)

[A]=0.109M

Hence, the molarity after a reaction time of 5.00 days is, 0.109 M

8 0
3 years ago
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