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o-na [289]
3 years ago
10

A 35 L tank of oxygen is at 315 K with an internal pressure of 190 atmospheres. How

Chemistry
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

600.7 moles

Explanation:

Applying,

PV = nRT................... Equation 1

Where P = Pressure of oxygen, V = Volume of oxygen, n = number of moles, R = molar gas constant, T = Temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

From the question,

Given: P = 190 atm, V = 35 L, T = 135 K

Constant: R = 0.082 atm.dm³/K.mol

Substitute these values into equation 2

n = (190×35)/(135×0.082)

n = 600.7 moles of xygen

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3 years ago
Lt takes 4 hr 39 min for a 2.00-mg sample of radium-230 to decay to 0.25 mg. what is the half-life of radium-230?
Rufina [12.5K]
Radioactive decay => C = Co { e ^ (- kt) |

Data:

Co = 2.00 mg
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t = 4 hr 39 min

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C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

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2) Use C / Co  = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

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6 0
4 years ago
Determine the net number of sigma bonds, the net number of pi bonds, and the overall bond order for N2+. Use 0.5 to indicate a f
trapecia [35]

Answer:

Net number of sigma bonds = 1

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Overall bond order = 3

Explanation:

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1s2 2s2 2p3

There is head to head overlap in pz orbital. Thus, there is one sigma bond

Pi bond is formed whenever there is side wise overlapping. Since both px and py undergoes overlapping to form pi bond, there are two pi bonds

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= 0.5 (8-2) = 0.5*6 = 3

5 0
3 years ago
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