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3 years ago

9

Acids containing polyatomic ions are named according to the name of the anion. true or false

1 answer:

Ray Of Light [21]3 years ago

5 0

Answer:

true

Explanation:

Names for such acids consist of the prefix “hydro-“, the first syllable of the anion, and the suffix “-ic”. Complex acid compounds have oxygen in them. For an acid with a polyatomic ion, the suffix “-ate” from the ion is replaced with “-ic.”

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Urgent plzz help meeee thx I HAVE EXAMEEE

USPshnik [31]

Answer: $2Ag^{+}(aq)+CO_3^{2-}(aq)\rightarrow Ag_2CO_3(s)$

Explanation:

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

$2AgF(aq)+Na_2CO_3(aq)\rightarrow Ag_2CO_3(s)+2NaF(aq)$

The complete ionic equation is;

$2Ag^{+}(aq)+2F^-(aq)+2Na^+(aq)+CO_3^{2-}(aq)\rightarrow Ag_2CO_3(s)+2Na^+(aq)+2F^-(aq)$

The ions which are present on both the sides of the equation are $Na^+$ and $F^-$ and are not involved in net ionic equation.

Hence, the net ionic equation is :

$2Ag^{+}(aq)+CO_3^{2-}(aq)\rightarrow Ag_2CO_3(s)$

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3 years ago

How does the solubility of a gas change with decreasing temperature? A. It increases. B. It decreases. C. It is uniform. D. Temp

vitfil [10]

A it increases is the correct answer.

Good luck and I hope this helps.!

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3 years ago

In physical changes, the atoms or molecules that compose the matter do not change their identity, even though the matter may cha

aalyn [17]

True. Physical changes only affect the inter-molecular bonding and structure.

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3 years ago

Can someone match the following ????

Arte-miy333 [17]

I believe it the answer is 3412

4 0

3 years ago

A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit

Triss [41]

Answer:

The final pressure is approximately 0.78 atm

Explanation:

The original temperature of the gas, T₁ = 263.0 K

The final temperature of the gas, T₂ = 298.0 K

The original volume of the gas, V₁ = 24.0 liters

The final volume of the gas, V₂ = 35.0 liters

The original pressure of the gas, P₁ = 1.00 atm

Let P₂ represent the final pressure, we get;

$\dfrac{P_1 \cdot V_1}{T_1} = \dfrac{P_2 \cdot V_2}{T_2}$

$P_2 = \dfrac{P_1 \cdot V_1 \cdot T_2}{T_1 \cdot V_2}$

$P_2 = \dfrac{1 \times 24.0 \times 298}{263.0 \times 35.0} = 0.776969038566$

∴ The final pressure P₂ ≈ 0.78 atm.

4 0

3 years ago