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andrew11 [14]
3 years ago
11

Can someone help me solve this problem (i)-(7-8i)

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
6 0
I represents \sqrt{-1} then there is the imaginary part, and the real part
the i is the imaginary
the 7 is the real part
distribute
i-(7-8i)
i-1(7-8i)
i-7+8i
-7+9i
it is normally writtnen in a+bi where a is the real part and b is the imaginary part

so the answer is -7+9i
Anna11 [10]3 years ago
5 0
(i) - (7 - 8i)
(0 + i) - (7 - 8i)
0 - 7 + i + 8i
-7 + 9i
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Given:

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A line passes through the point (-5,-3) and perpendicular to the given line.

To find:

The equation of the line.

Solution:

Slope intercept form of a line is:

y=mx+b                 ...(i)

Where, m is the slope and b is the y-intercept.

We have,

y=-\dfrac{5}{7}x+2          ...(ii)

On comparing (i) and (ii), we get

m=-\dfrac{5}{7}

We know that the product of slopes of two perpendicular lines is always -1.

m_1\times m_2=-1

-\dfrac{5}{7}\times m_2=-1

m_2=\dfrac{7}{5}

Slope of the required line is \dfrac{7}{5} and it passes through the point (-5,-3). So, the equation of the line is:

y-y_1=m_2(x-x_1)

y-(-3)=\dfrac{7}{5}(x-(-5))

y+3=\dfrac{7}{5}(x+5)

Using distributive property, we get

y+3=\dfrac{7}{5}(x)+\dfrac{7}{5}(5)

y+3=\dfrac{7}{5}x+7

y=\dfrac{7}{5}x+7-3

y=\dfrac{7}{5}x+4

Therefore, the equation of the line is y=\dfrac{7}{5}x+4. Hence, option A is correct.

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Step-by-step explanation:

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sertanlavr [38]
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