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Sav [38]
3 years ago
6

I really need help

Mathematics
1 answer:
Alex3 years ago
3 0

Answer:

See step by step

Step-by-step explanation:

To find if a function intervals are possible, make sure the points are above the x axis.

The graph is getting positve around x=-3 but it isn't positive yet.

The graph is positve until x=-1

The graph becomes positive again again at x=2 and is positive infinitely forever.

So let set up our interval

We are going to start at -3 since that where it start getting positive, we then going to use the greater than sign since it get positve as we go to the right as of right now. We use the greater than becuase we are not going to include -3 as our solutions.

We then use a less than sign since the answer must be less than -1 becuase around-1 it start getting negative.

It becomes positive again at x=2 so since we going to left to right use the greater than sign becuase we are not including 2.

It infinitely becomes positive so our interval is x must be cause greater than w becuase it can be any interval greater than two.

- 4 > x <  - 1

and

2 < x

The roots or zeroes are the x intercept of the graph,(when y=0, what is the x value.)

The x intercepts are -3 and 2.

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hi i'm really struggling with this and its due later today! If someone could show the work of how to do it and the answer that w
GuDViN [60]

Answer:

\frac{-5 \pm \sqrt{13} }{6}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\frac{-5 \pm \sqrt{5^2-4(3)(1)} }{2(3)}<u />

<u />

<u>Step 2: Evaluate</u>

  1. Evaluate Exponents:                    \frac{-5 \pm \sqrt{25-4(3)(1)} }{2(3)}
  2. Evaluate Multiplication:               \frac{-5 \pm \sqrt{25-12} }{6}
  3. Evaluate Subtraction:                  \frac{-5 \pm \sqrt{13} }{6}
8 0
3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
oksano4ka [1.4K]

Answer:

a.) dx3x² + 2

Use the properties of integrals

That's

integral 3x² + integral 2

= 3x^2+1/3 + 2x + c

= 3x³/3 + 2x + c

= x³ + 2x + C

where C is the constant of integration

b.) x³ + 2x

Use the properties of integrals

That's

integral x³ + integral 2x

= x^3+1/4 + 2x^1+1/2

= x⁴/4 + 2x²/2 + c

= x⁴/4 + x² + C

c.) dx6x 5 + 5

Use the properties of integrals

That's

integral 6x^5 + integral 5

= 6x^5+1/6 + 5x

= 6x^6/6 + 5x

= x^6 + 5x + C

d.) x^6 + 5x

integral x^6 + integral 5x

= x^6+1/7 + 5x^1+1/2

= x^7/7 + 5/2x² + C

Hope this helps

8 0
3 years ago
You weigh a gallon of liquid in science class and learn that it is approximately 7.7 pounds. You pass the liquid to the next gro
IceJOKER [234]

Answer:

7.7 pounds = 3.5 kilograms

Step-by-step explanation:

Given that,

Weight of a gallon of liquid = 7.7 pounds

We need to find weight in kilograms.

We must know the relation between pounds and kilograms and it is as follows :

1 kilogram = 2.20 pounds

or

1 pounds = (1/2.2) kilograms

7.7 pounds = (7.7/2.2) kilograms

= 3.5 kilograms

Hence, 7.7 pounds is equal to 3.5 kilograms.

4 0
3 years ago
Please help<br>step by step<br>Parentheses, Braces, and Brackets​
AURORKA [14]

Answer:

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3 years ago
I need help for 12xy-15x+6xy
choli [55]
The answer is 18xy-15x
 
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