200,000 because the numbers in the middle are low
Answer:
first option
Step-by-step explanation:
Given
f(x) =
← factorise the numerator
=
← cancel (x + 4) on numerator/ denominator
= 2x - 3
Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is
x = - 4
Substitute x = - 4 into the simplified f(x) for y- coordinate
f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11
The discontinuity occurs at (- 4, - 11 )
To obtain the zero let f(x) = 0, that is
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = 
There is a zero at (
, 0 )
Thus
discontinuity at (- 4, - 11 ), zero at (
, 0 )
It would be (a) because it is now
it
Answer:
see the explanation
Step-by-step explanation:
we know that
The sum of the interior angles in any polygon is given by the formula

where
n is the number of sides of the polygon
step 1
Find the sum of the interior angles in the given polygon
we have

substitute

step 2
Find the value of x
we know that

solve for x


step 3
Find the measure of each interior angle
substitute the value of x
Angle A

Angle B

Angle C

Angle D

Angle E

The answer is B i had this problem.