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SIZIF [17.4K]
3 years ago
15

Can someone help me ​

Mathematics
1 answer:
algol [13]3 years ago
7 0

Answer:

A)310.18g/mol

B)84.9947g/mol

C)108.01 g/mol

d)159.7g /mole(Approx)

e)Coc12 g/mol

f) A1(OH)3 g/mol

g)83.9949 g/mol

h)197.9 g/mol

i)18.01529 g/mol

Step-by-step explanation:

Hope u happy with my answer...

please mark me as brainlest

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What would be the first step to solving the equation? K+2=5
MrRissso [65]

Answer:

subtract 2 from both sides

Step-by-step explanation:

if you subtract 2 from both sides you will get k=3

6 0
3 years ago
Which of the following expressions are equivalent?
Dmitry [639]

Answer:

B. 7(6x – 1) and 42x – 7 is equivalent

Step-by-step explanation:

A. –3(3x + 5) and –9x + 5

=–3(3x + 5)=-9x-15 not equivalent

B. 7(6x – 1) and 42x – 7

7(6x – 1)=42x-7 equivalent

C. –6(4x – 3) and –6x

=–6(4x – 3)=-24+18 not equivalent

D. 5(2x + 3y) and 25xy

=5(2x + 3y)=10x+15y not equivalent.

4 0
3 years ago
The ratio of girls to boys in the 6th grade is to 6to7 how many girls are there if there are 364total students
Rina8888 [55]

Answer:

168 girls.

Step-by-step explanation:

There are a total of 6 + 7 = 13 'parts'.

So one part = 364 / 13 = 28.

So the number of girls = 6 * 28

= 168.

4 0
3 years ago
Suppose a shoe factory produces both low-grade and high-grade shoes. The factory produces at least twice as many low-grade as hi
umka2103 [35]

Answer:

The factory should produce 166 pairs of high-grade shoes and 364 pairs of low-grade shoes for maximum profit

Step-by-step explanation:

The given parameters for the shoe production are;

The number of low grade shoes the factory produces ≥ 2 × The number of high-grade shoes produced by the factory

The maximum number of shoes the factory can produce = 500 pairs of shoes

The number of high-grade shoes the dealer calls for daily ≥ 100 pairs

The profit made per pair of high-grade shoed = Birr 2.00

The profit made per of low-grade shoes = Birr 1.00

Let 'H', represent the number of high grade shoes the factory produces and let 'L' represent he number of low-grade shoes the factory produces, we have;

L ≥ 2·H...(1)

L + H ≤ 500...(2)

H ≥ 100...(3)

Total profit, P = 2·H + L

From inequalities (1) and (2), we have;

3·H ≤ 500

H ≤ 500/3 ≈ 166

The maximum number of high-grade shoes that can be produced, H ≤ 166

Therefore, for maximum profit, the factory should produce the maximum number of high-grade shoe pairs, H = 166 pairs

The number of pairs of low grade shoes the factory should produce, L = 500 - 166 = 334 pairs

The maximum profit, P = 2 × 166 + 1 × 364 = 696

6 1
3 years ago
Read 2 more answers
7.5x10^5-2.9x10^4=? having trouble
alexira [117]
721,000 should be the answer. took me a little while though haha
7 0
3 years ago
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