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grandymaker [24]

3 years ago

6

ursula earns $9 per hour.to write an expression that tells how much ursula earns h hours,joshua wrote 9/h.sarah wrote 9h. hwose

expression is correct and why

1 answer:

yawa3891 [41]3 years ago

7 0

Nine dollars per hour is
$9h

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velikii [3]

Whatever you do to one side, you have to do to the other.
Try to get all the x values and regular values together.
To do that, just subtract both sides by 6x to cancel it out on one side and subtract it from the other side:

6x-6x+32=-2x-6x
=
32=-8x
now divide both sides by -8 to get the x by itself

32/-8=-8/-8x
= 32/-8=x
-4=x
so your answer is: x= -4

5 0

3 years ago

A right triangle has legs that are 11 inches and 13 inches long what is the area of the triangle

blsea [12.9K]

143 the i answer is 143

hope this helps

7 0

3 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

3 years ago

Solve<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%20%5Ctimes%202%282%20%5Ctimes%204%29%7D%7B8%7D%20" id="TexFormula1" ti

creativ13 [48]

The answer is three you have to times the top numbers and divide

8 0

2 years ago

Read 2 more answers

How do you fully reduce 40/56 to lowest terms?

vladimir2022 [97]

10/19. 40/4=10, and 56/4=19. therefore the answer is 10/19.

5 0

3 years ago