Answer:
6/16 dogs will not be able to smell.
Explanation:
Genes A and B are considered for scent smell.
Individuals homozygous for either one or both of the nonfunctional recessive alleles are not able to smell.
The final cross would be AaBb x AaBb which has outcome of;
Individual with homozygous nonfunctional recessive alleles (bold ones):
- One nonfunctional recessive alleles: Aabb, aaBB, aaBb, Aabb, aaBb (5/16)
- Two nonfunctional recessive alleles: aabb (1/16)
- All nonfunctional recessive alleles: 6/16 dogs that could not smell scents
Answer:
17
Explanation:
In corn,
Smooth kernel (S) is dominant to rough kernel (s)
Purple kernel (P) is dominant to yellow kernel (p)
Since no information has been given about the cross here let us assume it to be a standard dihybrid cross.
The phenotypic ratio of dihybrid cross is 9:3:3:1. 9/16 will show dominant phenotype for both traits, 3/16 will show dominant phenotype for one trait, other 3/16 will show dominant phenotype for the second trait, 1/16 will have recessive phenotype for both the traits.
Here,
Purple rough (P_ss) = 52
Yellow smooth (ppS_) = 50
Both of them show dominant phenotype for one trait so they each form 3/16 of the progeny.
If the total progeny was z, 3/16*z = 50
z = (50*16)/3 = 267
Total progeny = 267 kernels
Yellow rough kernels (ppss) = (1/16*267) = 17
So approximately 17 corn kernels will be yellow and rough.
Answer:
b=6
Explanation:
f(x)=x3 - 3x2 + bx - 6
f(3)=27-27+3b-6
0=3b-6
3b=6
therfore
b=6/3
b=6
plz amrk me as brainleiest
Je dirais que c'est vrai car le gabbro est une roche à grain grossier et il est igné, ce qui signifie qu'il a été formé par le refroidissement et la solidification du magma ou de la lave. Je n'en suis pas tout à fait sûr, mais c'est mon avis, et je m'excuse pour toute erreur de grammaire car le français n'est pas ma langue maternelle.
