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Gnoma [55]
3 years ago
12

In dogs, genes A and B are required for scent.Individuals homozygous for either one or both of the nonfunctional recessive allel

es are not able to smell.If a large number of matings were made between two double heterozygotes, what percentage of offspring would not be able to smell? Express your answer as a fraction (i.e. 1/10)
Biology
1 answer:
andrew11 [14]3 years ago
5 0

Answer:

6/16 dogs will not be able to smell.

Explanation:

Genes A and B are considered for scent smell.

Individuals homozygous for either one or both of the nonfunctional recessive alleles are not able to smell.

The final cross would be AaBb x AaBb which has outcome of;

Individual with homozygous nonfunctional recessive alleles (bold ones):

  • One nonfunctional recessive alleles: Aabb, aaBB, aaBb, Aabb, aaBb (5/16)
  • Two nonfunctional recessive alleles: aabb (1/16)
  • All nonfunctional recessive alleles: 6/16 dogs that could not smell scents
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So, if we cross Cc x Cc, it results in the genotype ratio of 1 (CC) : 2 (Cc) : 1 (cc)

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Same is the case with male partner due to the probability that he would be the carrier is 1/2

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Now, the probability that the offspring will have the disease = product of all the above probabilities. (The probability of occurrence of two independent events is equal to the product of their individual probabilities).

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