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Kay [80]
3 years ago
10

8. A hiker walks 2.3 km east and then 4.1 km north. What is her displacement?

Physics
1 answer:
Zolol [24]3 years ago
8 0
Firstly , draw the path 2.3 to east and 4.1 to the north. you’ll get a right - angle triangle . the hypotenuse is the displacement.

to find the distance , use Pythagoras theorem.

let the displacement = c

c ^ 2 = 2.3 ^ 2 + 4.1 ^ 2

c = 4.7 km

then , you need to find the angle.

tan theta = 4.1 / 2.3

theta = 61 degree

i am sorry if my answer was wrong but i hope it helps you and you can understand it : )
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Question 23
bonufazy [111]

If the gymnast mass were doubled, her height (h) from the top of the board would be as follows,

с  Stay the same

Explanation:

  • The Mass of an object or body does not affect the acceleration due to gravity in any kind of way.
  • Light weight objects accelerate more slowly than the heavy objects because when the forces other than the gravity also plays a major role.
  • Mass increases of a body when an object has higher velocity or the speed.
  • The greater the force of gravity, it would give a direct impact on the object's acceleration; thus considering only a force, the heavier the object is, it would accelerate faster. But an acceleration depends upon the two factors which are  force and mass.
  • Newton's second law of motion states that the acceleration of an object is dependent upon the two factors which are, the net force of an object and the mass of the object.

3 0
3 years ago
The net horizontal force on a car is 981 N. The car has a mass of 1550 kg and the force is applied when the car has a speed of 2
viktelen [127]

Answer:

Distance, d = 778.05 m                          

Explanation:

Given that,

Force acting on the car, F = 981 N

Mass of the car, m = 1550 kg

Initial speed of the car, v = 25 mi/h = 11.17 m/s

We need to find the distance covered by car if the force continues to be applied to the car. Firstly, lets find the acceleration of the car:

F=ma\\\\a=\dfrac{F}{m}\\\\a=\dfrac{981}{1550}\\\\a=0.632\ m/s^2

Let d is the distance covered by car. Using second equation of motion as :

d=ut+\dfrac{1}{2}at^2\\\\d=11.17\times 35+\dfrac{1}{2}\times 0.632\times (35)^2\\\\d=778.05\ m

So, the car will cover a distance of 778.05 meters.

5 0
4 years ago
Astronomers use many different pieces of equipment to study space: optical telescopes on Earth, space telescopes, and space prob
Kobotan [32]
Then it would be C if D has been eliminated
8 0
3 years ago
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the angular speed of an automobile engine is increased at a constant rate from 1300rev/min to 2000rev/min in 3s (a) what is its
GalinKa [24]

Answer:

please find attached pdf

Explanation:

Download pdf
8 0
3 years ago
The nucleus of an atom is composed of unchanged particles as well as of the following
Ivan
I suppose that you wanted write "uncharged". The particles without electrical charge present in the nucleus are called neutrons.
7 0
3 years ago
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