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Bas_tet [7]
4 years ago
9

One factor that drives atmospheric circulation is the movement of air from warm equatorial areas to cooler areas.

Physics
2 answers:
Debora [2.8K]4 years ago
4 0

One factor that drives atmospheric circulation is the movement of air from warm equatorial areas to cooler areas.

This is true.


leva [86]4 years ago
3 0

The atmosphere is that thin gaseous envelope that surrounds our planet; it is not at all motionless in relation to the Earth; On the contrary, it is constantly animated by various movements.

These movements of the atmosphere have extremely variable characteristics:

- sometimes, it's a pleasant breeze that comes to refresh us, by a beautiful summer afternoon, when we are at the seaside;

- sometimes, it is violent winds which sweep a large part of France while wrapping around a vast zone of low pressures; from time to time these winds are so violent that they can uproot trees and make roofs fly away;

- and, sometimes, these movements of the atmosphere are in the form of fast ascents, with vertical speeds of the order of 10 m / s; these ancestries are localized, occurring on a small horizontal surface, of the order of a square kilometer, and they can give rise to a cloud of storm, the famous cumulonimbus.

Although this list is far from complete, it illustrates the great diversity of atmospheric movements.

so that's true


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A sled is pushed to right with a force of 200 N. The force of friction opposing that motion is 50 N. a) What is the Net Force on
marin [14]

Answer:

Fr = 150 [N]

a = 5 [m/s²]

Explanation:

In order to find the resulting force, we must assume that the thrust force is positive to the right, while the friction force is negative to the left.

F_{r}=200-50\\F_{r}=150[N]

Now Newton's Second Law tells us that the sum of the forces or the resulting force is equal to the product of mass by acceleration.

F = m*a

150 = 30*a\\a=150/30\\a = 5 [m/s^{2} ]

4 0
3 years ago
Please help!
tankabanditka [31]

Answer:

35 cm

Explanation:

There's a -0.50N force at 20cm.

There's another -0.50N force at 50cm.

You apply a force of F at a position x.

Sum of the forces:

∑F = ma

F − 0.5 N − 0.5 N = 0

F = 1.0 N

Sum of the moments (or torques):

∑τ = Iα

(-0.50 N) (20 cm) + (-0.50 N) (50 cm) + (1.0 N) (x) = 0

x = 35 cm

6 0
4 years ago
Hii:) anyone able to explain and help me with this question?
Assoli18 [71]

Answer:

No

Explanation:

The equation of state for ideal gases tells that:

pV=nRT

where

p is the gas pressure

V is the gas volume

n is the number of moles of the gas

R is the gas constant

T is the absolute temperature

In this problem, we have a fixed mass of gas. This means that the number of moles of the gas, n, does not change; also, the volume V remains the same, and R is a constant, this means that

p\propto T

So, as the pressure increases, the temperature increases.

However, here we want to understand what happens to the average distance between the molecules.

We have said previously that the number of moles n does not change: and therefore, the total number of molecules in has does not change either.

If we consider one dimension only, we can say that the average distance between the molecules is

d=\frac{L}{N}

where L is the length of the container and N the number of molecules. Since the volume of the container here does not change, L does not change, and since N is constant, this means that the average distance between the molecules remains the same.

4 0
3 years ago
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