Answer:
Explanation:
u = 4.6 x 10^6 m/s
Let E be the electric field
s = 3.5 cm = 0.035 m
v = 0
a = qE / m
So use third equation of motion
v^2 = u^2 - 2 a s
0 = (4.6 x 10^6)^2 - 2 x q E / m x 0.035
21.16 x 10^12 = 2 x 1.6 x 10^-19 x E / (1.67 x 10^-27 x 0.035)
E = 3865 N/C
(a) The magnitude of electric field is 3865 N/C
(b) the direction of electric field is opposite to the direction of motion of proton, i.e., towards left.
(c) Let t be the time taken
v = u + a t
0 = 4.6 x 10^6 - (1.6 x 10^-19 x 3865) t / (1.67 x 10^-27)
t = 1.24 x 10^-5 sec
(d) For electron, the direction of electric field is same the direction of electron, i.e., rightwards.
Use third equation of motion
v^2 = u^2 - 2 a s
0 = (4.6 x 10^6)^2 - 2 x q E / m x 0.035
21.16 x 10^12 = 2 x 1.6 x 10^-19 x E / (9.1 x 10^-31 x 0.035)
E = 2.1 N/C
Answer:
Jupiter
Explanation:
Since the mass of Jupiter is the greatest from the given choices, it will exert the most force on any object orbiting 100km above its surface.
This is compliance with the Newton's law of universal gravitation which states that "the force of attraction between two bodies is directly proportional to the magnitude of their masses and inversely proportional to the distances between them".
- Therefore, the more the masses of two bodies, the higher the gravitational attraction
- Since the distance is the same, the planet with the greater mass will exert the most force on the satellite.