Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
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Answer:
Well, the answer is simple. Everybody!
Explanation:
Answer:
E). User education and training.
Explanation:
In the context of network security, the most significant aspect of ensuring security from workstation cyberattacks would be 'education, as well as, training of the users.' <u>If the employee users are educated well regarding the probable threats and attacks along with the necessary safety measures to be adopted and trained adequately to use the system appropriately so that the sensitive information cannot be leaked</u> while working on the workstation and no networks could be compromised. Thus, <u>option E</u> is the correct answer.
Newton's 1st Law of Motion- an object (bear) will stay in motion until acted upon by an unbalanced force