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3 years ago

Please help! thank you

Mathematics

1 answer:

Dominik [7]3 years ago

7 0

Answer

15.7 meters squared.

Step-by-step explanation:

First you have to find the area of the small circle, using the formule A = 3.14(radius squared). So, 3.14(4) =12.56. Then you have to find the area of the bigger circle. A = 3.14(3 squared). A = 3.14(9) = 28.26. Finally, you subtract the area of the smaller circle from the bigger circle. 28.6 meters - 12.56 meters = 15.7 meters squared.

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Answer:

11.1%

Step-by-step explanation:

17/153= 0.111 x 100= 11.1%

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3 years ago

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Hoped I helped!

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3 years ago

Read 2 more answers

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Zigmanuir [339]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

114, 261, 319, 183,654,313,58,98,335,324,52,125,342,66,321,893,690,798,201,74,632,216,76,155,161,304,530,1110,93,631,75,344,264,1120,122,45,304,192,316,63

USING CALCULATOR :

The mean(m) of the data: = ΣX/n

n = sample size = 40

m = 12974/40

m = 324.4

Median = ((n + 1)/2) th term = 41/2 = (20 + 21)th term / 2

= (261 + 264) / 2 = 262.5

Standard deviation (s) = sqrt(Σ(x - m)²/n))

s = 281. 74

B.) Coefficient of skewness (Ks) :

3(mean - median) / standard deviation

3(324.4 - 262.5) / 281.74

= 0.66

Mild positive skewness Given a positive skew Coefficient value.

(d-1) Are there any outliers?

Yes

Four outliers

(d-2) What are the limits for outliers? (Round your answers to 1 decimal place. Negative amounts should be indicated by a minus sign.)

Lower bound = Q1 - (1.5 * IQR)

Upper bound = Q3 + (1.5 * IQR)

IQR = Q3 - Q1

Q3 = upper quartile = 343 ; Q1 = 106 ; Q2 = 262.5

IQR = 343 - 106 = 237

Lower bound = 106 - (1.5 * 237) = - 249.5

Upper bound = 343 + (1.5 * 237) = 698.5

-249.5 ≤ X ≤ 698.5

4 0

3 years ago

Statistics??? Construct a 95% confidence interval for the population mean. Assume the population has a normal distribution. A sa

antiseptic1488 [7]

Given:
μ = $3120, population mean
σ = $677, population standard deviation.
The population is normally distributed.
n = 20, sample size.

At the 95% confidence level, the confidence interval is
$( \mu - 1.96\frac{\sigma}{ \sqrt{n} } ,\, \mu + 1.96\frac{\sigma}{ \sqrt{n} })$

1.96(σ/√n) = 1.96(677/√20) = 296.71
Th confidence interval for the mean is
($2823.29, $3416.71)

Answer: ($2823.29, $3416.71)

6 0

3 years ago