Answer:
so the axis of symmetry is x=4
<em>Greetings from Brasil</em>
From radiciation properties:
![\large{A^{\frac{P}{Q}}=\sqrt[Q]{A^P}}](https://tex.z-dn.net/?f=%5Clarge%7BA%5E%7B%5Cfrac%7BP%7D%7BQ%7D%7D%3D%5Csqrt%5BQ%5D%7BA%5EP%7D%7D)
bringing to our problem
![\large{6^{\frac{1}{3}}=\sqrt[3]{6^1}}](https://tex.z-dn.net/?f=%5Clarge%7B6%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B6%5E1%7D%7D)
<h2>∛6</h2>
Answer:
C
Step-by-step explanation:
Translate the image 2 units right and 1 unit up. Then rotate the image 180°.
Take the coordinate W, it is at (2, 4).
Translate 2 units right (add 2 to the x coordinate) and 1 up (add 1 to the y coordinate)
(2, 4) ------> (2 + 2, 4 + 1) -------> (4, 5)
A rotation of 180° (doesn't matter the direction) makes the coordinates their opposites. Positives become negatives and negatives become positive.
(4, 5) -------> (-4, -5)
Answer:
B -1/5
you have to follow pemdas first get rid of the parethase which leaves you with 2+3x+6x=-4x+8x+1 then you add what you can do then you get 2+9x=4x+1 then you subtract 2 from both sides and subtract 4x from both sides which leaves you with 5x=-1 then you divide 5 from both sides and get x=-1/5
The probability that a randomly selected professor is female and feels "About Right" is 0.40
The distribution table :
____About right _ Oweight _ Uweight __ Total
Female _ 80 _____ 39 ______ 3 _______ 122
Male ___ 52 _____ 10 ______ 16 _______ 88
Total ___ 132 ____ 49 ______ 19 _______ 200
Oweight = Overweight
Uweight = Underweight
Recall :
Probability = required outcome / Total possible outcomes
Probability that a selected professor is female and feels 'About right' :
Required outcome = number of female professors who feels 'About right' = 80
Total number of professors = 200
Hence,
P(Female and 'About right') = 80/200 = 0.40
Learn more : brainly.com/question/11234923
